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Illusion [34]
3 years ago
9

10 cookie someone eats 4 of them he ate what percentage of the cookies

Mathematics
1 answer:
Virty [35]3 years ago
4 0

Answer:

40%

Step-by-step explanation:

10/4 = .4

.4 = 40%


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The mean hourly wage for employees in goods-producing industries is currently $24.57 (Bureau of Labor Statistics website, April,
Karolina [17]

Answer:

a)Null hypothesis:\mu = 24.57  

Alternative hypothesis:\mu \neq 24.57  

b) df=n-1=30-1=29  

Since is a two sided test the p value would be:  

p_v =2*P(t_{(29)}  

c)  If we compare the p value and the significance level assumed \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the true mean is different from 24.57 at 5% of signficance.

d)  For this case since we have a two tailed test we need to find two critical values and we need 0.025 of the area on each tail of the t distribution with 29 degrees of freedom. The critical values are given by:

t_{crit}=\pm 2.045

And the rejection zone would be given by:

(-\infty , -2.045) U(2.045,\infty)

Since pur calculated value is not on the rejection zone we Fail to reject the null hypothesis.

Step-by-step explanation:

The mean hourly wage for employees in goods-producing industries is currently $24.57. Suppose we take a sample of employees from the manufacturing industry to see if the mean hourly wage differs from the reported mean of $24.57 for the goods-producing industries.

a. State the null and alternative hypotheses we should use to test whether the population mean hourly wage in the manufacturing industry differs from the population mean hourly wage in the goods-producing industries.

We need to conduct a hypothesis in order to check if the mean is equal to 24.57 or not, the system of hypothesis would be:  

Null hypothesis:\mu = 24.57  

Alternative hypothesis:\mu \neq 24.57  

b. Suppose a sample of 30 employees from the manufacturing industry showed a sample mean of $23.89 per hour. Assume a population standard deviation of $2.40 per hour and compute the p-value.

\bar X=23.89 represent the sample mean  

s=2.4 represent the sample standard deviation

n=30 sample size  

\mu_o =24.57 represent the value that we want to test

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

If we analyze the size for the sample is = 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{23.89-24.57}{\frac{2.4}{\sqrt{30}}}=-1.552    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=30-1=29  

Since is a two sided test the p value would be:  

p_v =2*P(t_{(29)}  

c. With  α = 0.05  as the level of significance, what is your conclusion?

If we compare the p value and the significance level assumed \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the true mean is different from 24.57 at 5% of signficance.

d. Repeat the preceding hypothesis test using the critical value approach.

For this case since we have a two tailed test we need to find two critical values and we need 0.025 of the area on each tail of the t distribution with 29 degrees of freedom. The critical values are given by:

t_{crit}=\pm 2.045

And the rejection zone would be given by:

(-\infty , -2.045) U(2.045,\infty)

Since pur calculated value is not on the rejection zone we Fail to reject the null hypothesis.

4 0
2 years ago
A distribution of probabilities for random outcomes of a bivariate or dichotomous random variable is called a Group of answer ch
slega [8]

A distribution of probabilities for random outcomes of bivariate or dichotomous random variables is called (A) binomial probability distribution.

<h3>What is a binomial probability distribution?</h3>
  • The binomial distribution with parameters n and p in probability theory and statistics is the discrete probability distribution of the number of successes in a succession of n separate experiments, each asking a yes-no question and each with its own Boolean-valued outcome: success or failure.
  • The binomial distribution is widely used to describe the number of successes in a sample of size n selected from a population of size N with replacement.
  • If the sampling is done without replacement, the draws are not independent, and the resulting distribution is hypergeometric rather than binomial.
  • Binomial probability distribution refers to a distribution of probabilities for random outcomes of bivariate or dichotomous random variables.

As the description itself says, binomial probability distribution refers to a distribution of probabilities for random outcomes of bivariate or dichotomous random variables.

Therefore, a distribution of probabilities for random outcomes of bivariate or dichotomous random variables is called (A) binomial probability distribution.

Know more about binomial probability distribution here:

brainly.com/question/9325204

#SPJ4

Complete question:

A distribution of probabilities for random outcomes of bivariate or dichotomous random variables is called a ______.

Group of answer choices

(A) binomial probability distribution

(B) distribution of expected values

(C) random variable distribution

(D) mathematical expectation

5 0
2 years ago
What are some reasons to live I could use them right now
Yuliya22 [10]

Answer:

mom will be sad

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Nichol walks at a constant pace of 1.2 m/s and takes 15 minutes to get to school.
liraira [26]

Answer:

The difference between the distances they walked is 600 meters.

Step-by-step explanation:

Let's calculate the distance traveled by Nichol and Sakura with the following equation:

d = v*t

Where:

v: is the speed

t: is the time

The distance traveled by Nichol is:

d_{n} = 1.2 m/s*15min*\frac{60 s}{1 min} = 1080 m

And the distance traveled by Sakura is:

d_{s} = 1.4 m/s*20 min*\frac{60 s}{1 min} = 1680 m

Hence, the difference between the distances they walked is:

d_{t} = d_{s} - d_{n} = 1680 m - 1080 m = 600 m

Sakura traveled 600 meters more than Nichol.

Therefore, the difference between the distances they walked is 600 meters.

               

I hope it helps you!                    

4 0
2 years ago
An 18 ounce box of cereal costs $2.76. How many ounces should a box priced at $2.07 contain?
Darya [45]
First you find the unit rate. (Divide 2.76 by 18)
You will find out that each ounce costs $0.15

Then divide 2.07 by 0.15.

The answer is 13.8 ounces.

5 0
3 years ago
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