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puteri [66]
1 year ago
10

The graph of y=f(x) is the solid black graph below. Whoch function represents the dotted line

Mathematics
1 answer:
Savatey [412]1 year ago
4 0

The function that represents the dotted line of the graph using transformation rules is; f(x - 1) - 4.

<h3>How to Interpret Translation of Graphs?</h3>

For the function f(x) of the given graph,  when we look at the solid line, we see that it has a root at x = -1 which means it has a zero at x = -1.

However, when observing the dashed line, we see that it has a root at x = 0 which means it has a zero at x = 0.

Thus, we can  deduce from transformation rules that the function was moved by 1 unit to the right to get the new function.

Secondly, we observe that the dashed line is also below the function f(x), and we observe further that 4 was subtracted. Therefore, when we use the transformation rules again for subtracting from a function, we get the final function as; f(x - 1) - 4.

Read more about Translation of Graphs at; brainly.com/question/26238840

#SPJ1

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If f(x) = 3x - 1 and g(x) = x + 2, find (f+ g)(x).
Volgvan

Answer:

4x+1

Step-by-step explanation:

Since you're finding (f+g) (x), it means you are adding f(x) and g(x) together.

so you add: (3x-1) and (x+2)

combining like terms, you get 4x and 1, which means (f+g)(x)= 4x+1

4 0
3 years ago
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Step-by-step explanation:

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3 years ago
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when I double my number, add four, and then subtract my number and subtract 3, I get my number plus 1
Musya8 [376]
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3 0
3 years ago
Write a formula for a Riemann sum for the function f (x )equals 1089 minus x squared over the interval ​[0,33​].
Mashcka [7]

Answer:

Area of 23958

Step-by-step explanation:

The Riemann sum is just the divide of a area into smaller areas and computing the sum of those areas. It is basically the integral of a function over an interval.

\int\limits {1089-x^2} \, dx

over the interval [0,33].

\int\limits {1089-x^2} \, dx=1089x-(x^3)/3

evaluate

=0-1089\cdot{33}-(33^3)/3=35937-11979=23958

4 0
3 years ago
According to a survey of 500, the mean income before taxes of consumer units (i.e., households) inthe U.S. was $60,533 with a st
ioda

Answer:

The margin of error for constructing a 95% confidence interval on the population mean income before taxes of all consumer units in the U.S is 1406.32.

Step-by-step explanation:

We are given that according to a survey of 500, the mean income before taxes of consumer units (i.e., households) in the U.S. was $60,533 with a standard error of 717.51.

Margin of error tells us that how much our sample mean value deviates from the true population value.

<u></u>

<u>Margin of error is calculated using the following formula;</u>

        Margin of error =  Z_(_\frac{\alpha}{2}_) \times \text{Standard of Error}

where, \alpha = level of significance = 1 - confidence level

                                                    = 1 - 0.95 = 0.05 or 5%

Standard of Error =  \frac{\sigma}{\sqrt{n} } = 717.51

Now, the value of z at 2.5% level of significance (\frac{0.05}{2} =0.025) is given in the z table as 1.96, that means;

            Margin of error =  Z_(_\frac{\alpha}{2}_) \times \text{Standard of Error}

                                      =  1.96 \times 717.51 = 1406.32

Hence, the margin of error for constructing a 95% confidence interval on the population mean income before taxes of all consumer units in the U.S is 1406.32.

3 0
4 years ago
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