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Darya [45]
3 years ago
6

Which graph represents the solution set of the system of inequalities? x+y<1, 2y≥x−4

Mathematics
1 answer:
Sophie [7]3 years ago
7 0

The graph to the top left

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Simplify:
svetoff [14.1K]

Answer:

Uh I got 7x^2 + 16x +64. Idk if there are more options that aren't in the pic or if I did it wrong

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Can someone please help?!
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Answer:

Plot the points (0,0) and (1,3) to make the line.

Step-by-step explanation:

We know that a linear equation is y=mx+b, m is the slope and b is the y-intercept. We can see that the slope is m=3, and there is no b meaning b=0. Since the y-intercept is 0 we can start from the origin (0,0). The slope is 3/1 or known as rise/run. You go up 3 and go right 1, making the second point (1,3). This should work.

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2 years ago
( -20 , 14 ) and ( 30, 18)<br> Slope, Explanation needed please HELPPPPPP
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The formula to find the slope is (y2-y1)/(x2-x1)

If you plug in the numbers, you get (18-14)/(30-(-20))

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So your answer is 2/25

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A square with a side length of 2 units is dilated on a coordinate plane using the origin as the center of dilation. The resultin
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Write 9x² - 36x = 4y² + 24y + 36 in standard form
Kisachek [45]

Answer:

9·x² - 36·x = 4·y² + 24·y + 36 in standard form is;

(x - 2)²/2² - (y + 3)²/3² = 1

Step-by-step explanation:

The standard form of a hyperbola is given as follows;

(x - h)²/a² - (y - k)²/b² = 1 or (y - k)²/b² - (x - h)²/a² = 1

The given equation is presented as follows;

9·x² - 36·x = 4·y² + 24·y + 36

By completing the square, we get;

(3·x - 6)·(3·x - 6) - 36 = (2·y + 6)·(2·y + 6)

(3·x - 6)² - 36 = (2·y + 6)²

(3·x - 6)² - (2·y + 6)² = 36

(3·x - 6)²/36 - (2·y + 6)²/36 = 36/36 = 1

(3·x - 6)²/6² - (2·y + 6)²/6² = 1

3²·(x - 2)²/6² - 2²·(y + 3)²/6² = 1

(x - 2)²/2² - (y + 3)²/3² = 1

The equation of the hyperbola  is (x - 2)²/2² - (y + 3)²/3² = 1.

5 0
2 years ago
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