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statuscvo [17]
3 years ago
9

Assume that thermometer readings are normally distributed with a mean of 0 degrees C and a standard deviation of 1.00 degrees C.

A thermometer is randomly selected and tested. For the case below, draw a sketch, and find the probability of the reading. (The given values are in celsius degrees)
Between -1.42 and 1.61
The probability of getting a reading between -1.42 degrees C and 1.61 degreesC is_______ ( round to four decimal places as needed)
Mathematics
1 answer:
Cerrena [4.2K]3 years ago
4 0

Answer:

The probability of getting a reading between -1.42 degree C and 1.61 degree C is 0.8685.

Step-by-step explanation:

We are given that

Mean,\mu=0 degree C

Standard deviation, \sigma=1 degree C

We have to find the probability of the reading between -1.42 and 1.61.

P(-1.42

P(-1.42

P(-1.42

Using the formula

P(a

P(-1.42

P(-1.42

Hence, the probability of getting a reading between -1.42 degree C and 1.61 degree C is 0.8685.

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Use a truth table to verify the first De Morgan law (p ∧ q)’ ≡ p’ ∨ q’.
Nutka1998 [239]

Answer:

(p ∧ q)’ ≡ p’ ∨ q’

Step-by-step explanation:

First, p and q have just four (4) possibilities, p∧q is true (t) when p and q are both t.

p ∧    q

t t t

t f f

f f t

f f f

next step is getting the opposite

(p∧q)'

    <em>f</em>

<em>     t</em>

<em>     t</em>

<em>     t</em>

Then we get p' V q', V is true (t) when the first or the second is true.

p' V  q'

f  <em>f</em>  f

f  <em>t</em>  t

t  <em>t</em>  f

t  <em>t</em>  t

Let's compare them, ≡ is true if the first is equal to the second one.

(p∧q)'   ≡     (p' V q')

    <em>f              f </em>

<em>     t              t</em>

<em>     t              t</em>

<em>     t              t</em>

Both are true, so

(p ∧ q)’ ≡ p’ ∨ q’

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Last two answer for both or no brainleist
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Step-by-step explanation:

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Step-by-step explanation:

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2 years ago
3 3/5 + 9 3/5 answer with a mixed number in simplest form
Romashka [77]

Both fractions have the same denominator so it's going to be easy. First set up your equation:

3 \frac{3}{5} + 9 \frac{3}{5}

Add the whole numbers:

3 + 9 = 12

Now add the fractions:

\frac{3}{5} + \frac{3}{5} = \frac{6}{5}

add both together:

12 + \frac{6}{5} = 12 \frac{6}{5}

\frac{6}{5} is an improper fraction so change it:

12 \frac{6}{5} = 13 \frac{1}{5}

Since 6 is one more than 5, add 1 to the whole number and subtract the numerator and denominator(6 - 5 = 1) and make the remaining the new numerator. That leaves you with 13 \frac{1}{5}

Your answer is 13 \frac{1}{5}

3 0
3 years ago
Sheldon wants to buy a laptop that costs $ 450 from an electronics store . He has two coupons to choose from coupon A which give
Gekata [30.6K]

Answer:

Coupon B

Step-by-step explanation:

Given

Price = \$450

Coupon\ A = \$80

Coupon\ B = 20.5\%

Required

Which coupon is better

From the question, we have:

Coupon\ A = \$80

Coupon\ B = 20.5\%

Coupon B means that:

Coupon\ B = 20.5\% * \$450

Coupon\ B = 0.205 * \$450

Coupon\ B = \$92.25

By comparison:

Coupon B gives him a better buy because: \$92.25 > \$80

7 0
3 years ago
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