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statuscvo [17]
3 years ago
9

Assume that thermometer readings are normally distributed with a mean of 0 degrees C and a standard deviation of 1.00 degrees C.

A thermometer is randomly selected and tested. For the case below, draw a sketch, and find the probability of the reading. (The given values are in celsius degrees)
Between -1.42 and 1.61
The probability of getting a reading between -1.42 degrees C and 1.61 degreesC is_______ ( round to four decimal places as needed)
Mathematics
1 answer:
Cerrena [4.2K]3 years ago
4 0

Answer:

The probability of getting a reading between -1.42 degree C and 1.61 degree C is 0.8685.

Step-by-step explanation:

We are given that

Mean,\mu=0 degree C

Standard deviation, \sigma=1 degree C

We have to find the probability of the reading between -1.42 and 1.61.

P(-1.42

P(-1.42

P(-1.42

Using the formula

P(a

P(-1.42

P(-1.42

Hence, the probability of getting a reading between -1.42 degree C and 1.61 degree C is 0.8685.

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saw5 [17]

Answer:

\large\boxed{2.02\times10^{-7}}

Step-by-step explanation:

The scientific notation:

a\cdot10^k\\\\1\leq a

We have:

(8.08\times10^{-10})\div(4.0\times10^{-3})\\\\=\dfrac{8.08\times10^{-10}}{4.0\times10^{-3}}\\\\=\dfrac{8.08}{4}\times\dfrac{10^{-10}}{10^{-3}}\qquad\text{use}\ \dfrac{a^n}{a^m}=a^{n-m}\\\\=2.02\times10^{-10-(-3)}\\\\=2.02\times10^{-7}

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Solve for n:<br> 3⁄5 · n = 6
garik1379 [7]

Answer:

n = 10

Step-by-step explanation:

Solve for n:

(3 n)/5 = 6

Multiply both sides of (3 n)/5 = 6 by 5/3:

(5×3 n)/(3×5) = 5/3×6

5/3×3/5 = (5×3)/(3×5):

(5×3)/(3×5) n = 5/3×6

5/3×6 = (5×6)/3:

(5×3 n)/(3×5) = (5×6)/3

(5×3 n)/(3×5) = (3×5)/(3×5)×n = n:

n = (5×6)/3

6/3 = (3×2)/3 = 2:

n = 5×2

5×2 = 10:

Answer:  n = 10

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