Answer:
Its actually one solution it is solvable and only has one solution
Step-by-step explanation:
The required simplified value of b + g is 21.
Given that,
At a classroom costume party, the average age of the b-boys is g, and the average age of the g girls is b.
The average age of everyone at the party (all these boys and girls, plus their 42- year-old teacher) is b+g,
<h3>What is average?</h3>
The average of the values is the ratio of the total sum of values to the number of values.
Here,
The average age of the b-boys is g.
The average age of the g-girls is b.
The average age of everyone at the party (all these boys and girls, plus their 42-year-old teacher) is b+g,
Now,
average of n = 3 (b , g , b+g)
Average = g + b + 42 / 3
b + g = (b + g + 42 ) / 3
3b + 3g = b + g + 42
3b - b + 3g - g = 42
2b + 2g = 42
2 (b + g) = 42
b + g = 21
Thus, the required simplified value of b + g is 21.
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Answer:
No. X's above 2: 1
Above 3: 1
Above 4: 3
Above 5: 3
Step-by-step explanation:
Drawing a line plot of a data set means that you record the number of times that particular value shows up in the set. 2 on the line plot would only have 1 'X' placed above it because there is only one 2 in the data set:
5, 5, 4, 3, 2, 5, 4, 4
3 would also have 1 'X' above it because there is also only one 3 in the data set:
5, 5, 4, 3, 2, 5, 4, 4
Similarly, 4 and 5 would both have three 'X's because there are three 4's and three 5's in the data set:
4's: 5, 5, 4, 3, 2, 5, 4, 4
5's: 5, 5, 4, 3, 2, 5, 4, 4
Hope this helped!
The radius of the given circle is 5 units with the equation x²+y²+8x-6y+21=0.
<h3>
What are circles?</h3>
All points in a plane that are at a certain distance from the center combine to form a circle.
It is the curve that a moving point in a plane draws to keep its distance from another point constant, to put it another way.
In the center of a circle, equal chords subtend equal angles.
So, the radius of the circle with equation x² + y² + 8x – 6y + 21 = 0:
General form:
(x – a)² + (y-b) = r²
x² + y² – 2ax – 2by + (a² + b² – r²) = 0
We know that: r = √(a² +b²)
Compare the following equation to the equation's general form.
We obtain:
-2ax = 8x ⇒ a = – 4
-2by = -6y ⇒ b = 3
r = √((-4)2 +32 ) = √16 + 9 = √25 = 5
Therefore, the radius of the given circle is 5 units with the equation x²+y²+8x–6y+21=0.
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Correct question:
What is the radius of a circle whose equation is x² + y² + 8x – 6y + 21 = 0?