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almond37 [142]
3 years ago
7

What is the value of x?????

Mathematics
1 answer:
MakcuM [25]3 years ago
6 0
Tan(60)=opp/adj

Tan(60)= x/15

sqrt3= x/15    Cross multiply here

x= sqrt3 x 15 

The answer is A


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Effectus [21]

Answer:

Step-by-step explanation:

7 0
2 years ago
Solve each system using a matrix<br> 7x+2y=5<br> 13x+14y=-1
Svetach [21]

Solve each system using a matrix

7x+2y=5

13x+14y=-1Solve each system using a matrix

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2 years ago
Read 2 more answers
You rise 15 feet for every 1000 feet you drive forward, what is the slope?
liberstina [14]
The slope is:  \frac{3}{200} .
________________________________________________________
Note:
________________________________________________________
slope = rise/ run = 15 ft/ 1000 ft ;

          = 15/1000 = (15÷15) / (1000÷15) ;

            =  1/ (200/3) = 1* (3/200) = [tex] \frac{3}{200} [/tex] .
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3 0
2 years ago
What's the sum of an infinite geometric series if the first term is 156 and the common ratio is 2∕3?
DENIUS [597]

Answer:

468

Step-by-step explanation:

Formula for infinite sum of geometric series is;

S_∞ = a1/(1 - r)

Where;

a1 is first term

r is common ratio

We are given;

a1 = 156

r = ⅔

Thus;

S_∞ = 156/(1 - ⅔)

S_∞ = 156/(⅓)

S_∞ = 468

4 0
2 years ago
A cookie factory monitored the number of broken cookies per pack yesterday.
trapecia [35]

Answer:

Confidence Interval - 2.290 < S < 2.965

Step-by-step explanation:

Complete question

A chocolate chip cookie manufacturing company recorded the number of chocolate chips in a sample of 50 cookies. The mean is 23.33 and the standard deviation is 2.6. Construct a 80% confidence interval estimate of the standard deviation of the numbers of chocolate chips in all such cookies.

Solution

Given  

n=50

x=23.33

s=2.6

Alpha = 1-0.80 = 0.20  

X^2(a/2,n-1) = X^2(0.10, 49) = 63.17

sqrt(63.17) = 7.948

X^2(1 - a/2,n-1) = X^2(0.90, 49) = 37.69

sqrt(37.69) = 6.139

s*sqrt(n-1) = 18.2

s\sqrt{\frac{n-1}{X^2 _{(n-1), \frac{\alpha }{2} } } \leq \sigma \leq s\sqrt{\frac{n-1}{X^2 _{(n-1), 1-\frac{\alpha }{2} } }

confidence interval:

(18.2/7.948) < S < (18.2/6.139)

2.290 < S < 2.965

8 0
2 years ago
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