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lions [1.4K]
3 years ago
5

Marta's dog just had six puppies. Four are female (F), and two are male (M). One of the males is brown. Two of the females are b

rown. All puppies are either brown or white. If Marta randomly gives away puppies to her friends, what is the probability of a friend getting a puppy that is male, brown, or both?
Mathematics
1 answer:
aev [14]3 years ago
5 0

Answer:

Step-by-step explanation:

No of total brown = 2 + 1 = 3 .

probability = 3 / 6

= 1 /2 .

no of males = 2

probability

= 2 / 6

= 1 /3

no of person who is both male and brown = 1

probability = 1 /6

Required probability

= probability of being brown + probability of being male - probability of being both

= 1 / 2 + 1 / 3 - 1 /6

= 4 / 6

= 2 / 3 .

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Answer:

The 95% confidence interval for the true population mean dog weight is between 62.46 ounces and 71.54 ounces.

Step-by-step explanation:

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\alpha = \frac{1-0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

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The upper end of the interval is the sample mean added to M. So it is 67 + 4.54 = 71.54 ounces.

The 95% confidence interval for the true population mean dog weight is between 62.46 ounces and 71.54 ounces.

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4 years ago
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