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lions [1.4K]
3 years ago
5

Marta's dog just had six puppies. Four are female (F), and two are male (M). One of the males is brown. Two of the females are b

rown. All puppies are either brown or white. If Marta randomly gives away puppies to her friends, what is the probability of a friend getting a puppy that is male, brown, or both?
Mathematics
1 answer:
aev [14]3 years ago
5 0

Answer:

Step-by-step explanation:

No of total brown = 2 + 1 = 3 .

probability = 3 / 6

= 1 /2 .

no of males = 2

probability

= 2 / 6

= 1 /3

no of person who is both male and brown = 1

probability = 1 /6

Required probability

= probability of being brown + probability of being male - probability of being both

= 1 / 2 + 1 / 3 - 1 /6

= 4 / 6

= 2 / 3 .

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What is the slope of the line that passes through these points in decimal form
mestny [16]

Answer:

-1.25

Step-by-step explanation:

(3,8)   (7,3)

(8-3)/(3-7)= 5/-4= -1.23

FYI: watch some videos on Khan academy on finding slope

4 0
2 years ago
Given the domain {-2, 1, 5}, what is the range for the relation 4x + y = 3?
steposvetlana [31]

Answer:

Step-by-step explanation:

Domain is the set of all possible inputs (x) for the function f(x)

The range is the set of all possible values for that domain

This function is 4x + y = 3 which can be re-written as y = 3-4x

Plug in each of the domain values and you will get the range

For -2 : y = 3-4(-2) = 3 + 8 = 11

For 1:  y = 3-4(1) = -1

For 5: y = 3-4(5) = -17

So range is {-17, -1, 11}  

6 0
1 year ago
Dean Halverson recently read that full-time college students study 20 hours each week. She decides to do a study at her universi
romanna [79]

Answer: The p-value is 0.154.

Step-by-step explanation:

Since we have given that

We claim that

Null hypothesis :

H_0:\mu=20

Alternate hypothesis :

H_1:\mu

Population mean = 20 hours

Sample mean = 18.5 hours

Sample standard deviation = 4.3 hours

Sample size n = 35

So, test statistic would be

z=\dfrac{\bar{X}-\mu}{\dfrac{\sigma}{\sqrt{n}}}\\\\z=\dfrac{18.5-20}{\dfrac{4.3}{\sqrt{35}}}\\\\z=\dfrac{-1.5}{0.726}\\\\z=-2.066

So, the  p value would be 0.154.

Hence, the p-value is 0.154.

4 0
3 years ago
0.05 is 1/10 the value of what
Dafna1 [17]

Answer:

0.05

Explanation:

Let x = the number

.05 = .1x

5/100 = (1/10)x       Multiply both sides by 10.

5/10 = x

1/2 = x

8 0
3 years ago
In a sample of 70 stores of a certain​ company, 62 violated a scanner accuracy standard. It has been demonstrated that the condi
uysha [10]

Answer:

We need at least 243 stores.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error of the interval is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

For this problem, we have that:

n = 70, p = \frac{62}{70} = 0.886

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

Determine the number of stores that must be sampled in order to estimate the true proportion to within 0.04 with 95​% confidence using the​ large-sample method.

We need at least n stores.

n is found when M = 0.04. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.04 = 1.96\sqrt{\frac{0.886*0.114}}{n}}

0.04\sqrt{n} = 1.96\sqrt{0.886*0.114}

\sqrt{n} = \frac{1.96\sqrt{0.886*0.114}}{0.04}

(\sqrt{n})^{2} = (\frac{1.96\sqrt{0.886*0.114}}{0.04})^{2}

n = 242.5

Rounding up

We need at least 243 stores.

5 0
2 years ago
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