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Afina-wow [57]
3 years ago
11

Jordan created a scale drawing of a rectangular room. The drawing is 8 inches long by 6 inches wide. He used a scale of 1 inch -

3 feet. What is the area, in square feet,
Mathematics
1 answer:
liubo4ka [24]3 years ago
4 0

Answer: 144 feet

Step-by-step explanation:

Well solving for area you multiply length times wedth. So multiply 8 and 6 to get 48. Now you have to convert 48 inches into feet. So just multiply 48 times 3 to get 144.

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2. Morgan ran 5 miles in 57 and a half minutes. How long did it take her to run each
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11.4 because do 57 divided by 5 equals 11.4 to run each mile
4 0
3 years ago
What is the prime factorization if 6400 using exponents
katovenus [111]

So prime factorization is as it seems, finding the prime factors for a number. With this number, break it down as such:

\underbrace{6400}_{\underbrace{64}_{\underbrace{8}_{\underbrace{4}_{\boxed{2*2}} \boxed{2}}*\underbrace{8}_{\underbrace{4}_{\boxed{2*2}}\boxed{2}}}*\underbrace{100}_{\underbrace{10}_{\boxed{5*2}}*\underbrace{10}_{\boxed{5*2}}}}

<u>Looking at our factors, the prime factorization of 6400 is 2^8*5^2</u>

5 0
3 years ago
Lucy has two star systems left to visit on her voyage, but her ship is running low on fuel. The first system, KA-77, is 12001200
-Dominant- [34]

Answer:

 1348 light years.    

Step-by-step explanation:

Please find the attachment.

Let x represent the distance between KA-7 and KA-11.

We have been given that the first system, KA-7, is 1200 light years away while the second system, KA-11, is 1700 light years away. Lucy sees an angle of 52 degrees between KA-7 and KA-11.

We can see from our attachment that Lucy, KA-7 and KA-11 forms a triangle and we will use law of cosines to solve for x.  

(AB)^2=(AC)^2+(BC)^2-2(AC)(BC)*cos (C)

Upon substituting our given values in above formula we will get,

x^2=1200^2+1700^2-2*1200*1700*cos (52^o)  

x^2=1440000+2890000-4080000*0.615661475

x^2=4330000-2511898.81933008

x^2=1818101.18066992

Let us take square root of both sides of our equation.

x=\sqrt{1818101.18066992}

x=1348.3698234\approx 1348

Therefore, KA-7 and KA-11 are approximately 1348 light years apart.

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3 years ago
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2 years ago
Finding Domain.
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