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MatroZZZ [7]
3 years ago
10

Help pls :))))))))))))

Mathematics
1 answer:
Aneli [31]3 years ago
6 0

Answer:

yes, the triangle are congruent by SAS

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Find the simplified quotient of y^2+y/y^2-2y/4y+4/y^2-4y+4
babunello [35]

Answer:

y4 - 8y3 + 8y2 + 2y + 8

 —————————————

           2y2          

Step-by-step explanation:

Step  1  :

            4

Simplify   ——

           y2

Equation at the end of step  1  :

            y       y       4

 (((((y2)+————)-((2•—)•y))+——)-4y)+4

          (y2)      4      y2

Step  2  :

           y

Simplify   —

           4

Equation at the end of step  2  :

            y       y       4

 (((((y2)+————)-((2•—)•y))+——)-4y)+4

          (y2)      4      y2

Step  3  :

            y

Simplify   ——

           y2

Dividing exponential expressions :

3.1    y1 divided by y2 = y(1 - 2) = y(-1) = 1/y1 = 1/y

Equation at the end of step  3  :

          1  y2   4

 (((((y2)+—)-——)+——)-4y)+4

          y  2   y2

plz mark me as brainliest :)

6 0
3 years ago
What is the answer to 4 1/6 - 8/9
Sergeu [11.5K]

4 1/6 - 8/9

= 4 3/18 - 16/18

= 3 21/18 - 16/18

= 3 5/18


answer

3 5/18

4 0
3 years ago
Read 2 more answers
Solve this im stuck please solve!
Elena-2011 [213]
There is 6 triangles & 2 rectangles
7 0
3 years ago
Read 2 more answers
A. 30<br> B.45<br> C. 90<br> D. 60
BabaBlast [244]

Answer:

<u>C. 90</u>

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Julie and Eric row their boat (at a constant speed) 18 miles downstream for 3 hours helped by the current. Rowing at the same ra
Nastasia [14]

Answer

Find out the the rate of the boat in still water.

To proof

let us assume that the speed of the boat in the still water = u

let us assume that the speed of the current = v

Formula

speed = \frac{Distance}{time}

As given

18 miles downstream for 3 hours

Now for the downstream

u + v = \frac{18}{3}

u + v = 6

now for the upstream

As given

the trip back against the current takes 6 hours

u - v = \frac{18}{6}

u-v = 3

Than the two equation becomes

u + v = 6 and u - v = 3

add both the above equation

we get

2u = 9

u = 4.5miles per hour

put this in the  u - v = 3

4.5 -v = 3

v =1.5 miles per hour

The rate of  the boat in the still water is  4.5miles per hour .

Hence proved



3 0
3 years ago
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