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MatroZZZ [7]
3 years ago
8

A card is drawn at random from a standard pack of playing cards. Then a fair coin is flipped. What is the probability of selecti

ng a 5 and the coin landing on tails?
Mathematics
2 answers:
RoseWind [281]3 years ago
8 0

Answer:

the probability of getting 5 from standard deck is 4/52 and probability to get tails from a flipped coin is 1/2

Step-by-step explanation:

as there are 4 parts in card i.e spade diamonds hearts and clubs which has 13 cards each from each 13 cards there are one 5 card so there are 4 cards with 5 number in standard deck

there is only one tails in a coin

serg [7]3 years ago
7 0

Answer:

The order doesn’t matter, as the two events are probabilistically independent of one another. There are 13 spades in a standard 52 card deck, so the probability of drawing  the number 5 is 13/52 or 1/4. The probability of heads is 1/2. The probability of both occurring is the product of the two probabilities, or 1/4*1/2 = 1/8 or 12.5%.

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What are the domain and range of the function f(x)=sqrt(x-7) +9
GenaCL600 [577]

Domain: x ≥ 7

Range (7,9)

5 0
4 years ago
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Pleaseeeeeeeeee helppp!!! I will mark brainliest!!
Arada [10]

Answer:

Fourth Quadrant

Step-by-step explanation:

a>0 = a is a positive number = +y

b<0 = b is a negative number = -x

[-b,-a] = [-(-x), -(+y)] = [x, -y]

[positive, negative] is on the fourth quadrant

3 0
3 years ago
Name the property used in: (5 + 2) + n = 7 + n
rjkz [21]
Additive indentity
(5 + 2) + n
n = 1
a variable is always a number itself remember 7+n
5+2 = 7
5 0
4 years ago
In order to estimate the average time spent on the computer terminals per student at a local university, data were collected fro
VladimirAG [237]

Answer:

Margin of error  for a 95% of confidence intervals is 0.261

Step-by-step explanation:

<u>Step1:-</u>

 Sample n = 81 business students over a one-week period.

 Given the population standard deviation is 1.2 hours

 Confidence level of significance = 0.95

 Zₐ = 1.96

Margin of error (M.E) = \frac{Z_{\alpha  }S.D }{\sqrt{n} }

Given n=81 , σ =1.2 and  Zₐ = 1.96

<u>Step2:-</u>

<u />Margin of error (M.E) = \frac{Z_{\alpha  }S.D }{\sqrt{n} }<u />

<u />Margin of error (M.E) = \frac{1.96(1.2) }{\sqrt{81} }<u />

On calculating , we get

Margin of error = 0.261

<u>Conclusion:-</u>

Margin of error  for a 95% of confidence intervals is 0.261

<u />

4 0
4 years ago
Use the circle graph to determine how many hours per day Becky spends on each activity.
Oduvanchick [21]
404 error: graph not found

anyway, the graph was not included. since the sleep time was included, I will assume that the circle graph is worth 24 hours

all we need to do is to convert the percentages to fractions and multiply that by 24 to find out how many hours per activity


percent means parts out of 100 so x%=x/100


so we have
School
Eating
Sleep
Homework
Free Time

School=25%
25%=25/100=1/4
1/4 times 24=6
School: 6 hours


Eating=10%
10%=10/100=1/10
1/10 times 24=2.4
Eating: 2.4 hours


Sleep=40%
40%=40/100=4/10=2/5
2/5 times 24=48/5=9.6
Sleep: 9.6 hours


Homework=10%
10%=10/100=1/10
1/10 times 24=2.4
Homework: 2.4 hours


Free Time=15%
15%=15/100=3/30
3/20 times 24=72/20=36/10=3.6
Free Time: 3.6 Hours

Answers:
School: 6 hours
Eating: 2.4 hours
Sleep: 9.6 hours
Homework: 2.4 hours
Free Time: 3.6 Hours


3 0
4 years ago
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