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alexdok [17]
3 years ago
7

What theorem do we use to solve for a side of a right triangle?

Mathematics
2 answers:
melisa1 [442]3 years ago
6 0

Answer:

I would believe you are talking about the Pythagorean Theorem:

In that case the formula is <u>L^2 + L^2 = H^2.</u>

If you have the hypotenuse it is:

<u>H^2 - L^2 = L^2:</u>

When solving, just substitute your lengths for each side of the triangle.

Note: This only works with right triangles.

cestrela7 [59]3 years ago
6 0

Answer:

pythagorean theorem

Step-by-step explanation:

a^2 +b^2 =c^2

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Sue has $2.20 in dimes and nickels. If she has 13 more dimes than nickels, how many of each coin does she have?
dem82 [27]
10d+5n=220
divide both sides by 5
2d+n=44

d=13+n
sub 13+n for d in other equatin

2(13+n)+n=44
26+2n+n=44
26+3n=44
minus 26 both sides
3n=18
divide both sides by 3
n=6
sub back

d=13+n
d=13+6
d=19


19 dimes
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4 0
3 years ago
I will give brainlist A pentagonal prism has dimensions that are four times the dimensions of a similar pentagonal prism. So its
Vlada [557]

Answer:

The correct answer is 64

Step-by-step explanation:

we know that,

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=4×4×4

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7 0
3 years ago
Read 2 more answers
How do i write b + 3 = b^2 in verbal expression
igor_vitrenko [27]

Answer:

b plus 3 is equal to b squared

7 0
3 years ago
7. If the longer leg of a right triangle is twice as long as the shorter leg, what is the ratio of
kicyunya [14]

Answer: The ratio is 2.39, which means that the larger acute angle is 2.39 times the smaller acute angle.

Step-by-step explanation:

I suppose that the "legs" of a triangle rectangle are the cathati.

if L is the length of the shorter leg, 2*L is the length of the longest leg.

Now you can remember the relation:

Tan(a) = (opposite cathetus)/(adjacent cathetus)

Then there is one acute angle calculated as:

Tan(θ)  =  (shorter leg)/(longer leg)

Tan(φ) = (longer leg)/(shorter leg)

And we want to find the ratio between the measure of the larger acute angle and the smaller acute angle.

Then we need to find θ and φ.

Tan(θ) = L/(2*L)

Tan(θ) = 1/2

θ = Atan(1/2) = 26.57°

Tan(φ) = (2*L)/L

Tan(φ) = 2

φ = Atan(2) = 63.43°

Then the ratio between the larger acute angle and the smaller acute angle is:

R = (63.43°)/(26.57°) = 2.39

This means that the larger acute angle is 2.39 times the smaller acute angle.

5 0
3 years ago
Help me please !!!!!!
stira [4]

Yes, the relationship is proportional. 3 * 3.2 = 9.6. And 5 * 3.2 = 16.

3 0
3 years ago
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