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3 years ago

Solve using Quadratic Formula x^2 + 3x - 3 = 0

Mathematics

1 answer:

katrin [286]3 years ago

4 0

Answer:

a= 1 , b= 3 , c= –3

$x = \frac{ - b \frac{ + }{} \sqrt{ {b}^{2} - 4ac} }{2a} \\ x = \frac{ - 3 \frac{ + }{} {} \sqrt{ {3}^{2} - 4(1)( - 3)} }{2(1)} \\ = \frac{ - 3 \frac{ + }{} \sqrt{9 + 12} }{2} = \frac{ - 3 \frac{ + }{} \sqrt{21} }{2} \\ \\ x = \frac{ - 3 \frac{ + }{} \sqrt{21} }{2} \\ \\ x = 0.79 \\ x = - 3.79$

I hope I helped you^_^

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3 years ago

F(x)=3 over x+2-x-3 squared what is f(7)

dimaraw [331]

Answer:

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Step-by-step explanation:

We are given the following function of x and we are to find the value of $f ( 7 )$ :

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Substituting the given value (7) in the above function to get:

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3 years ago

Read 2 more answers

Need to pass this test to graduate

Paraphin [41]

The 1st graph has vertex in (-3, -3) which can be translated into
Horizontal shift left 3
Vertical shift down 3
Other than that, the graph shows y=x^2 so it wasn't compressed or stretched

The 2nd graph has vertex in (0, 0) which mean there is no vertical and horizontal shift. But the graph is facing down and it was slimmer than y=x^2 graph. When x=1, the result is y=3 which was 3 times more than it supposed to be.
The graph must be:
Reflection across x-axis
Vertical stretch of 3

The 3rd graph has vertex in (3, -3) which can be translated into
Horizontal shift right 3
Vertical shift down 3
Same as the 1st graph, the 3rd graph shows y=x^2 so it wasn't compressed or stretched.

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3 years ago

Solve using Quadratic Formula x^2 + 3x - 3 = 0​

Solve using Quadratic Formula x^2 + 3x - 3 = 0