Twice a number increased by 5= 2x+5
5 decreased by twice a number= 5-2x
twice the difference of a number and 5= 2(x-5)
Twice the sum of a number and 5= 2(x+5)
Five subtracted from twice a number= 2x-5
Twice a number, less 5= 2x-5
Fifteen increased by a number
Answer:
Step-by-step explanation:
The question is incomplete. Here is the complete question.
The upper-left coordinates on a rectangle are (−5,6) and the upper-right coordinates are (−2,6). The rectangle has a perimeter of 16units. Draw the rectangle on the coordinate plane below.
If the coordinates of the top of the triangle (breadth) is (−5,6) and (−2,6), we can calculate the breadth of the rectangle by taking the difference between the two points using the formula:
D = √(y₂-y₁)²+(x₂-x₁)²
Given x₁ = -5, y₁= 6, x₂ = -2 and y₂ = 6
D = √(6-6)²+(-2-(-5))²
D = √0²+3²
D = √9
D = 3 units
Breadth = 3 units
Given the Perimeter to be 16 units and the formula for calculating the perimeter of rectangle t be P = 2(L+B), we can get the length of the rectangle.
16 = 2(3+L)
16 = 6+2L
16-6 = 2L
2L = 10
L = 10/2
L = 5 units.
<em>Hence the length of the rectangle is 5 units and the breadth is 3 units. Find the diagram in the attachment.</em>
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▹ Answer
<em>q = 16</em>
▹ Step-by-Step Explanation
3(q - 7) = 27
3q - 21 = 27
Add 21 to both sides:
21 + 21 = na
27 + 21 = 48
3q = 48
Divide both sides by 3:
3/3 = q
48/3 = 16
q = 16
Hope this helps!
CloutAnswers ❁
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Answer:
(0, 1)
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
<u>Algebra I</u>
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define Systems</u>
y + 5x = 1
5y - x = 5
<u>Step 2: Rewrite Systems</u>
y + 5x = 1
- Subtract 5x on both sides: y = 1 - 5x
<u>Step 3: Redefine Systems</u>
y = 1 - 5x
5y - x = 5
<u>Step 4: Solve for </u><em><u>x</u></em>
<em>Substitution</em>
- Substitution in <em>y</em>: 5(1 - 5x) - x = 5
- Distribute 5: 5 - 25x - x = 5
- Combine like terms: 5 - 26x = 5
- Isolate <em>x</em> term: -26x = 0
- Isolate <em>x</em>: x = 0
<u>Step 5: Solve for </u><em><u>y</u></em>
- Define equation: 5y - x = 5
- Substitute in <em>x</em>: 5y - 0 = 5
- Subtract: 5y = 5
- Isolate <em>y</em>: y = 1