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yanalaym [24]
3 years ago
13

According to the Americans with Disabilities Act, a ramp can rise no more than 1 ft for every 12 ft of horizontal distance. What

is the maximum angle that the ramp can form with the ground? a. 4.8º c. 5.0º b. 2.7º d. 3.7º
Mathematics
1 answer:
taurus [48]3 years ago
3 0

Answer:

A. 4.8°

Step-by-step explanation:

We have that,

The horizontal distance for the ramp = 12 feet.

Maximum height of the ramp = 1 feet.

So, we get that the value of the angle 'x' made by the ramp with the ground is given by,

\tan x=\frac{perpendicular}{base}

i.e. \tan x=\frac{1}{12}

i.e. \tan x=0.0833

i.e. x=\arctan 0.0833

i.e. x = 4.8°

Thus, the maximum angle made by the ramp with the ground is 4.8°.

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\displaystyle   GH  =  2 \sqrt{30}

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Step-by-step explanation:

<h3>QUESTION-2:</h3>

we are given a right angle triangle

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<h3>Question-1:</h3>

in order to figure out GH we can use Trigonometry because the given triangle is a right angle triangle

as we want to figure out GH we'll use sin function

remember that,

\displaystyle  \sin( \theta)  =  \frac{opp}{hypo}

let our opp, hypo and \theta be GH, 4√10 and 60° respectively

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\displaystyle  \sin(  {60}^{ \circ} )  =  \frac{GH}{4 \sqrt{10} }

recall unit circle:

\displaystyle   \frac{ \sqrt{3} }{2}   =  \frac{GH}{4 \sqrt{10} }

cross multiplication:

\displaystyle   2 GH  =  4 \sqrt{10}  \times  \sqrt{3}

simplify multiplication:

\displaystyle   2 GH  =  4 \sqrt{30}

divide both sides by 2:

\displaystyle   GH  =  2 \sqrt{30}

<h3>QUESTION-3:</h3>

Recall that, the sum of the interior angles of a triangle is 180°

therefore,

\displaystyle m \angle G +  {60}^{ \circ}  + {90}^{ \circ}  =  {180}^{ \circ}

simplify addition:

\displaystyle m \angle G +  {150}^{ \circ}  =  {180}^{ \circ}

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