Line. A line would have a length but has no width
Answer:
The change in delta x would be 0 in the second option because the change is exactly the same.
For every side you just add 90 to your equation. so #4 would be 360-125-125-55=(55)
Answer:The claim is correct
Explanation:Assume the given triangle ABCperimeter of triangle ABC = AB + BC + CA ............> I
Now, we have:D is the midpoint of AB, this means that:
AD = DB = (1/2) AB ..........> 1E is the midpoint of AC, this means that:
AE = EC = (1/2) AC ...........> 2DE is the midsegment in triangle ABC, this means that:
DE = (1/2) BC ...........> 3perimeter of triangle ADE = AD + DE + EA
Substitute in this equation with the corresponding lengths in 1,2 and 3:perimeter of triangle ADE = (1/2) AB + (1/2) BC = (1/2) AC
perimeter of triangle ADE = (1/2)(AB+BC+AC) .........> IIFrom I and II, we can prove that:perimeter of triangle ADE = (1/2) perimeter of triangle ABC
Which means that:perimeter of midsegment triangle is half the perimeter of the original triangle.
Hope this helps :)
The task is to find the original coordinates with the transformed ones given, so you have to apply the inverse of the stated transformations.
Q"( 6,-1),R"(0,-1) and S"(0,-7)
-> rotate 90 anti-clockwise
Q'(1,6), R'(1,0),S'(7,0)
-> translate left by 7 units
Q(-6,6), R(-6,0), S(0,0)