Answer:
"Multiply the previous value by 2"
Step-by-step explanation:
Let's check the first 2 terms for all the answer choices.
1. Add
to the previous value:
![\frac{1}{32}+\frac{1}{16}=\frac{3}{32}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B32%7D%2B%5Cfrac%7B1%7D%7B16%7D%3D%5Cfrac%7B3%7D%7B32%7D)
Doesn't match.
2. Subtract
from the previous value:
![\frac{1}{32}-\frac{1}{16}=-\frac{1}{32}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B32%7D-%5Cfrac%7B1%7D%7B16%7D%3D-%5Cfrac%7B1%7D%7B32%7D)
Doesn't match.
3. Divide the previous value by 2:
![\frac{\frac{1}{32}}{2}\\=\frac{1}{32}*\frac{1}{2}=\frac{1}{64}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cfrac%7B1%7D%7B32%7D%7D%7B2%7D%5C%5C%3D%5Cfrac%7B1%7D%7B32%7D%2A%5Cfrac%7B1%7D%7B2%7D%3D%5Cfrac%7B1%7D%7B64%7D)
Doesn't match.
4. Multiply the previous value by 2:
![\frac{1}{32}*2=\frac{2}{32}=\frac{1}{16}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B32%7D%2A2%3D%5Cfrac%7B2%7D%7B32%7D%3D%5Cfrac%7B1%7D%7B16%7D)
DOES WORK!
Also, doing the same thing with all the other values would give us matching answer. So this choice is right.
Answer:
20g
since mass should be in kg or gram if small then g
An expression for the total cost of the daycare for Lucy's dog this week is T = 3F + 2H and the total cost is equal to $114.
<h3>How to write an expression for the total cost?</h3>
In this exercise, you're required to write an expression for the total cost of the daycare for Lucy's dog this week. Thus, we would assign a variable to the cost for full-day and half-day day care as follows:
- Let the cost for full-day be F.
- Let the cost for half-day be H.
Thus, the total cost of the daycare is given by:
T = 3F + 2H
Evaluating the expression, we have:
T = 3(28) + 2(15)
T = 84 + 30
T = $114.
Read more on expressions here: brainly.com/question/12189823
#SPJ1
Answer:
Option A
Step-by-step explanation:
Area of the composite figure = Area of ΔABH + Area of BCGH + Area of ΔDEF
Area of ΔABH = ![\frac{1}{2}(\text{Base})(\text{Height})](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%28%5Ctext%7BBase%7D%29%28%5Ctext%7BHeight%7D%29)
= ![\frac{1}{2}(6)(8-5)](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%286%29%288-5%29)
= 9 in²
Area of the trapezoid = ![\frac{1}{2}(CG+BH)(\text{Distance between these lines})](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%28CG%2BBH%29%28%5Ctext%7BDistance%20between%20these%20lines%7D%29)
= ![\frac{1}{2}(6+4)(5)](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%286%2B4%29%285%29)
= 25 in²
Area of ΔDEF = ![\frac{1}{2}(8)(6)](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%288%29%286%29)
= 24 in²
Therefore, area of the given figure = 9 + 25 + 24
= 58 in²
Option A will be the correct option.
Answer: -7 is the answer
Step-by-step explanation:
4(2)+3(2-7)
2-7 is -5
-5 times 3 is -15
4 times 2 is 8
-15+8=-7