Answer:
- A: 24,500
- B: 11,800
- C: 12,700
Step-by-step explanation:
Since the number of A seats equals the total of the rest of the seats, it is half the seats in the stadium: 49000/2 = 24,500.
The revenue from those seats is, ...
24,500×$30 = $735,000
so the revenue from B and C seats is ...
$1,246,800 -735,000 = $511,800
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We can let "b" represent the number of B seats. Then there are 24500-b seats in the C section and the revenue from those two sections is ...
24b +18(24500-b) = 511800
6b = 70,800 . . . . . . . . . . . . . . . subtract 441000, collect terms
b = 70,800/6 = 11,800 . . . . . . . seats in B section
24,500 -11,800 = 12,700 . . . . . seats in C section
There are 24500 seats in Section A, 11800 seats in Section B, and 12700 seats in Section C.
2π is the period of `y = 1+ tan((1)/(2)x)`
Complex roots occur when b^2 - 4ac is negative.
So we have (-6)^2 - 4.1.k < 0
-4k < - 36
k > 9
Answer: 325 dollars
Step-by-step explanation:
In order to find out a percentage of somethin, you can simply multiply and divide
32500÷100= 325
