What is the area of rhombus ABCD ? Enter your answer in the box. Do not round at any steps. units² Rhombus A B C D on a coordina
te plane with vertex A at negative 1 comma 4, vertex B at 3 comma 2, vertex C at negative 1 comma 0, and vertex D at negative 5 comma 2. Point P is at negative 3.4 comma negative 1.2. Dashed segments join point P to point D and point P to point C, forming right angle D P C.
1 answer:
Answer:
16 units²
Step-by-step explanation:
Diagonal AC is a vertical line extending from y=0 to y=4, so is 4 units long.
Diagonal BD is a horizontal line extending from x=-5 to x=3, so is 8 units long.
The area of a rhombus is half the product of the lengths of the diagonals, so ...
A = (1/2)(4 units)(8 units) = 16 units²
The area of rhombus ABCD is 16 units².
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Part a is correct.
Part b can be done a couple ways.
1) Use binomial distribution. p = 0.2, n = 144
P(x>3) = 1 - P(x=0) -p(x=1) -p(x=2) -p(x=3)
where
2) Assume a normal distribution with mean = 28.2, stdev = 4.8
Look up z-value in normal table to find probability.
Hope that helps.
Part b can be done a couple ways.
1) Use binomial distribution. p = 0.2, n = 144
P(x>3) = 1 - P(x=0) -p(x=1) -p(x=2) -p(x=3)
where
2) Assume a normal distribution with mean = 28.2, stdev = 4.8
Look up z-value in normal table to find probability.
Hope that helps.