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prohojiy [21]
4 years ago
11

After the schedule adjustment, the first 36 runs were an average of 8 minutes late. As a result, the Boston public school distri

ct claimed that the schedule adjustment was an improvement-students were not as late. Assume a population standard deviation for bus arrival time of 12 minutes. Calculate the value of the test statistic

Mathematics
1 answer:
aev [14]4 years ago
6 0

Answer:

The value of test statistic is -2.

Step-by-step explanation:

The following information is missing in the question.

The population mean is 12 minutes.

We are given the following in the question:

Population mean, μ = 12 minutes

Sample mean, \bar{x} = 8 minutes

Sample size, n = 36

Population standard deviation, σ = 12 minutes

Formula:

z_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }

Putting all the values, we have

z_{stat} = \displaystyle\frac{8 - 12}{\frac{12}{\sqrt{36}} } = -2

The value of test statistic is -2.

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.55 of a box of chocolate are dark chocolate,0.3 are milk chocolate and the rest are white chocolate. There are 138 pieces more
lyudmila [28]

Answer: there were 345 pieces of chocolate in the box.

Step-by-step explanation:

Let x represent the number of pieces of chocolate there in the box.

0.55 of a box of chocolate are dark chocolate. This means that the number of dark chocolate in the box is 0.55x

0.3 are milk chocolate. This means that the number of milk chocolate in the box is 0.3x

The rest are white chocolate. This means that the number of white chocolate in the box is x(1 - 0.55 - 0.3) = 0.15x

There are 138 pieces more dark chocolate than white chocolate. This means that

0.55x - 0.15x = 138

0.4x = 138

x = 138/0.4

x = 345

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4 years ago
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alexgriva [62]

Answer:

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Step-by-step explanation:

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Rzqust [24]

Answer:

36 cm

Step-by-step explanation:

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Step-by-step explanation:

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