Find the solution to the following system of equations write as an ordered pair

1 answer:

7 0

Answer: (4,8)

First you have to solve for Y in either equation. I solved for Y in the second equation and my new equation was y=12-x.

Then you plug this new equation into the equation you did not touch. It will become 3x+ (12-x)=20.

Next you solve this equation for X which would be 4.

Lastly you plug in 4 in either equation. I plugged it in the first equation and it became 3(4)+y=20

I hope this helps some :)

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pickupchik [31]

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Read 2 more answers

How to do the problem

MrMuchimi

Order of operations are:
1. Parentheses (simplify inside 'em)
2. Exponents
3. Multiplication and Division (from left to right)
4. Addition and Subtraction (from left to right)

So, on your first one:
Parentheses first:
8(3+4)-2*8/(5-3)
8(7)-2*8/(2)

There are no exponents so multiplication and division:
56-16/2
56-8

Finally, addition and subtraction:
56-8=48

Your second problem is a bit more complicated but follows the same rules:
 $( 8^{2}+(13-4) ^{2} )/5$

Parentheses first:
 $( 8^{2}+ 9^{2})/5)$

Now, exponents. Even though they are inside parentheses, we can't go further until we simply those.
(64+81)/5

Now back to parentheses:
(145)/5

Division:
145/5=29

Hope that helps

8 0

3 years ago