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SashulF [63]
3 years ago
13

In one week 97 cell phones were sold. The following week, 48 more cell phones were sold than the week before. How many cell phon

es were sold in those 2 weeks
Mathematics
1 answer:
baherus [9]3 years ago
8 0

145. 7 + 8 is 15 carry the 1, 9+4+1 is 14, so 145

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(-7) x (-3)
Andreas93 [3]

Answer:

Positive

Step-by-step explanation: (-27) = 27

7 0
3 years ago
What is the probability of first drawing a red card, then a face card, and then a black card? Do not round your intermediate com
lozanna [386]

Answer:

 [ 26 / 425 ] ≈ 0.0612

Step-by-step explanation:

Solution:-

- First we will describe the standard deck of 52 cards in terms of black, red and face cards found in a standard deck

- Following is a table of distribution of colored and face card found in a standard deck:

                 Type                   Number of cards

                 1 - 10                                40

                 Black                               26

                 Red                                 26

                 Face                                12

- The numerical cards from digit ( 1 to 10 ) are found in all 4 suits ( Clubs, Diamonds, Spades, and Hearts ). Hence, 10 x 4 = 40

- The entire deck is split in two colors ( Red and Black ) equally. So, the number of Black and Red cards are = 52 / 2 = 26 cards.

- The face cards are of three types ( King, Queen and Jack ). These three face cards are found in each of the 4 suits. Hence, Total number of face cards are = 4 * 3 = 12

- We will now consider the probabilities asscociated with each type. We will define 3 events and write down their proability as expressed:

Event ( A ): First draw is a red card.

- The probability of this event can be determined with the help of the table given above. There are a total of 26 red card in a standard deck of 52 cards. Hence,

            p ( A ) = [ Number of red cards ] / [ Total cards in a deck ]

            p ( A ) = [ 26 ] / [ 52 ]

            p ( A ) = 1 / 2

- After we make the first draw of a red card. Our deck distribution is changed to Number of Red cards remaining = 25 and total deck now has 51 cards remaining.

- We will define the next event as:

Event ( B ): The second draw is a face card.

- The probability of this event can be determined with the help of the table given above. There are a total of 12 face cards in a standard deck of 52 cards which is now down to 51 cards. Hence,

            p ( B ) = [ Number of face cards ] / [ Total cards in a deck ]

            p ( B ) = [ 12 ] / [ 51 ]

            p ( B ) = 4 / 17

- After we make the first draw of a face card. Our deck distribution is changed to Number of Face cards remaining = 11 and total deck now has 50 cards remaining.

- We will define the next event as:

Event ( C ): The third draw is a black card.

- The probability of this event can be determined with the help of the table given above. There are a total of 26 black cards in the deck. The total number of cards are down to 50 cards only. Therefore,

            p ( C ) = [ Number of black cards ] / [ Total cards in a deck ]

            p ( C ) = [ 26 ] / [ 50 ]

            p ( C ) = 13 / 25

- The entire drawing process consists of 3 events which are dependent on each draw. However, for the overall event to occur i.e drawing a red card , then a face card, and then a black card. We will multiply all three outcomes as follows:

          p ( T ) = p ( A ) * p ( B ) * p ( C )

          p ( T ) = [ 1 / 2 ] * [ 4 / 17 ] * [ 13 / 25 ]

          p ( T ) =  [ 26 / 425 ] ≈ 0.0612

4 0
4 years ago
What is thiss?? Can someone help me pleaseee and like soon it’s find the missing number on the number line
mylen [45]
I believe the anwser to this question is -19
8 0
3 years ago
Equivalencia de-4n+1​
postnew [5]

Answer:

Please translate this to english for my help

Step-by-step explanation:

5 0
3 years ago
I need answer how to do number 3
Olegator [25]
You know that you need two already to make one hexagon. So, if you multiply, or add two four times, 2+2+2+2, you would get eight.
3 0
3 years ago
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