Considering the ballon to be spherical
It's volume is given by 4/3(π r^3) by differentiating volume with respect to time we get rate of change of volume hence,
4πr^2(dr/dt)=600÷60=10
Substituting r=30cm
4π(30)*(30)(dr/dt)=10
dr/dt=rate of increase in bullion's radius=1/(360π)cm/s
Answer:
The smaller number is 20.
Step-by-step explanation: You subtract 50-30 to get 20.
Answer:
Cars in one hour: 40 cars
Step-by-step explanation:
30 cars ---> 45 min
Xc ----------> 60 min
Xc = [(60min)*(30 cars)]/45 min
Xc = 40
Best regards
Divide both sides of this eq'n by -9. You'll get y = -1.
The answer would be 10.19m. If you want to round it of to a less precise measurement it would be 10 m. That is rounding of the decimal value to the ones place. the rule of rounding of is form 6 t0 9 it would add 1 to the nearest place value next to it and 0 - 5 will not.
