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Llana [10]
3 years ago
9

Consider the right triangular prism given AC = 9 cm

Mathematics
2 answers:
BaLLatris [955]3 years ago
6 0

Answer: A,B, and D

Step-by-step explanation:

nasty-shy [4]3 years ago
5 0

Answer:

A : The height of the prism is is 10 cm

B : DFG is  a base

D : The appropriate unit of measure for the volume is cubic centimetres

Step-by-step explanation:

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Suppose a company needs temporary passwords for the trial of a new payroll software. Each password will have one digit followed
Alekssandra [29.7K]

Answer:  The required number of passwords that can be created is 175760.

Step-by-step explanation:  Given that a company needs temporary passwords for the trial of a new payroll software.

Each password will have one digit followed by three letters and the letters can be repeated.

We are to find the number of passwords that can be created using this format.

For the one digit in the password, we have 10 options, 0, 1, 2, 3, 4, 5, 6, 7, 8 and 9.

Since there are 26 letters in English alphabet and letters can be repeated, so the number of options for 3 letters is

26 × 26 × 26 = 17576.

Therefore, the total number of ways in which passwords can be created using the given format is

n=9\times17576=175760.

Thus, the required number of passwords that can be created is 175760.

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4 years ago
Need help. 7.58 × 10^2<br><br> convert with a standard and scientific notation
mixas84 [53]
The answer is 0.00758
7 0
4 years ago
Simplify each expression:<br>5.) 4 4/5 + 3/4 × 2 1/4​
In-s [12.5K]

Answer: 6 39/80

Step-by-step explanation:

8 0
4 years ago
What are the solutions of the equation x6 + 6x3 + 5 = 0? Use factoring to solve. mc017-1.jpg and x = 1 mc017-2.jpg and x = –1 mc
Wittaler [7]

We are given equation :x^6+6x^3+5=0

Use\:the\:rational\:root\:theorem

\mathrm{Therefore,\:we\:need\:to\:check\:the\:following\:rational\:numbers:\quad }\pm \frac{1,\:5}{1}

-\frac{1}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x+1

\mathrm{Compute\:}\frac{x^6+6x^3+5}{x+1}\mathrm{\:to\:get\:the\:rest\:of\:the\:eqution:\quad }x^5-x^4+x^3+5x^2-5x+5

Therefore, final factored form it

x^6\:+\:6x^3\:+\:5=\left(x+1\right)\left(x^5-x^4+x^3+5x^2-5x+5\right)

We can't factor it more.

Therefore,

x+1=0.

x=-1.

Therefore, the real solution of the equation would be -1.


5 0
4 years ago
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Write each of the equations below in standard form (i.e. y = ax^2+bx+c y=ax ​2 ​​ +bx+c):
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C . Is the answer
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