3 years ago

Find the angle vector of 7j +10 k,i +6j+6k,-4i+9j+6k

Mathematics

1 answer:

aleksandrvk [35]3 years ago

7 0

Answer:

Right angled and isosceles

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If a=under root s(s-a)(s-b)(s-c) then the value of a, when a =3 b =4c = 5 and s =a+b+c by 2

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Step-by-step explanation:

Here it's given that ,

$\sf\red{\longrightarrow} A=\sqrt{s(s-a)(s-b)(s-c)}$

Also ,

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And we need to find out the value of A , when

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So , on substituting the respective values to find s we have ,

$\sf\red{\longrightarrow} s =\dfrac{3+4+5}{2}=\dfrac{12}{2}=\bf{6}$

Now let's find out A as ,

$\sf\red{\longrightarrow} A = \sqrt{6(6-3)(6-4)(6-5)} \\$

$\sf\red{\longrightarrow}A =\sqrt{6 * 3 * 2 * 1}\\$

$\sf\red{\longrightarrow} A = \sqrt{3^2 * 2^2 *1^2}\\$

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$\sf\red{\longrightarrow}\boxed{\qquad \blue{\bf A = 6 \qquad}}$

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2 years ago

Find the angle vector of 7j +10 k,i +6j+6k,-4i+9j+6k​

Find the angle vector of 7j +10 k,i +6j+6k,-4i+9j+6k