What are the perfect square factors of 3150

Mathematics

2 answers:

Alina [70]3 years ago

8 0

Answer:

9, 25, 225

Step-by-step explanation:

first of all we will find the factors of 3150

The factors of 3150 are as follows

2,3,5 ,6 7, 9, 10, 14, 15, 18, 21, 25, 30, 35, 42, 45,

50, 63, 70, 75, 90, 105, 126, 150, 175, 210, 225, 315, 350, 450, 525, 630, 1050,1575, 3150

Out of these factors perfect squares are

9, 25, 225

Dvinal [7]3 years ago

5 0

First, we must lay out all the factors of 3150 and they are:

1, 2, 3, 5, 6, 7, 9, 10, 14, 15, 18, 21, 25, 30, 35, 42, 45, 50, 63, 70, 75, 90, 105, 126, 150, 175, 210, 225, 315, 350, 450, 525, 630, 1050, 1575, 3150

Among these numbers, the only perfect square are:

9, 25, 225

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(Puzzle 2 - Scientific Notation Directions: Using the digits 1 to 9 to fill in the boxes only once, write the largest and smalle

leva [86]

Answer:

8x(10)^9 - 2 x (10)^1

1x(10)^3 - 9 x (10)^2

Step-by-step explanation:

3.1 X (10)^4- 6.5 X (10)^2

= 31000- 650

= 30,350

For greater number

_x10^blank - _ x 10^_

8x(10)^9 - 2 x (10)^1 ( we use 9 as the power because greater number used as power gives the bigger number and the next smaller number 8 as base. Similarly we use smaller number for power to get a smaller for the greatest difference)

= 8,000,000,000 -20

= 7,999,999,980

For smaller number

_x10^blank - _ x 10^_

1x(10)^3 - 9 x (10)^2 ( we use 3 as the power because smaller number used as power gives the smaller number and the next smallest number 1 as base. Similarly we use next smaller number for power to get the next smaller for the smallest difference)

= 1000- 900

= 100

We fill in the blanks keeping in mind that we do not have to repeat the numbers from 1-9 and also the numbers should have such an arrangement that they show the smallest and largest possible differences.

4 0

3 years ago

Which function is an odd function?

Annette [7]

I believe,the answer is c

3 0

3 years ago

one endpoint of AB has coordinates (-3,5) If the coordinates of the midpoint of AB are (2,-6),what is the length of AB?

avanturin [10]

We know that (-3,5) is the location of one of the endpoints.... and we know the midpoint is at (2,-6)... .now.. what's the distance between those two guys?

$\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
&({{ -3}}\quad ,&{{ 5}})\quad 
% (c,d)
&({{ 2}}\quad ,&{{ -6}})
\end{array}\qquad 
% distance value
d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}
\\\\\\
d=\sqrt{[2-(-3)]^2+[-6-5]^2}\implies d=\sqrt{(2+3)^2+(-6-5)^2}
\\\\\\
d=\sqrt{5^2+(-11)^2}\implies d=\sqrt{25+121}\implies d=\sqrt{146}$

so, the distance "d" from the midpoint to that endpoint is that much. And the distance from the midpoint to the other endpoint is the same "d" distance, because the midpoint is half-way in between both endpoints.

so, the length of AB is twice that distance, or $\bf 2\sqrt{146}$