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3 years ago

What is the simplified form of squared root 140?

Mathematics

2 answers:

kompoz [17]3 years ago

6 0

Its 2 square root of 35

irga5000 [103]3 years ago

6 0

ANSWERS to Algebra 1 B Unit 5: Radical Expressions and Data Analysis

1. D

2. B

3. A

4. B

5. D

100% correct 5/5

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70 POINTS HELP ME URGENT SHOW YOUR WORK

Feliz [49]

Answer:

x= the number of ride tickets

y= the total cost of admission plus how many ride tickets a person purchases

y= 1.25x + 9.5

It is a$1.25 per ticket for the rides at the fair, so it would be 1.25 multiplied by the amount of tickets that are purchased (x). Spencer bought 17 tickets, so 17x1.25= 21.25 and it says that he spent a total of $30.75 at the fair, so 30.75-21.25=9.5, so that means the cost of admission is $9.50.

Step-by-step explanation:

I hope this helps!

7 0

3 years ago

The average daily temperature, t, in degrees fahrenheit for a city as a function of the month of the year, m, can be modeled by

Vikentia [17]

The answer will be t = $sin((m.\frac{\pi}{6})+55)$ average daily temperature, t, in degrees Fahrenheit for a city as a function of the month of the year.

<h3>What is temperature?</h3>

Temperature is the degree or intensity of heat present in a substance or object, especially as expressed according to a comparative scale and shown by a thermometer or perceived by touch.

<h3>TO SOLVE:</h3>

$35cos(\frac{\pi}{6(m+3)}+55)\\\\35 cos(\frac{\pi m}{6} + 55 + \frac{\pi}{2})\\$

suppose $x = m.\frac{\pi}{6}+55$ and $\frac{\pi}{2} = 90$ degree

We know, cos(x+90°) = - sin(X)

⇒ $cos((m.\frac{\pi}{6})+55+90degree)$ degree = - $sin((m.\frac{\pi}{6})+55)$

⇒ t = $sin((m.\frac{\pi}{6})+55)$

Hence the answer will be t = $sin((m.\frac{\pi}{6})+55)$ average daily temperature, t, in degrees Fahrenheit for a city as a function of the month of the year.

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3 0

2 years ago

Last week, Ms. Herald walked 1.6 miles for 3 nights last week. She walked an

ikadub [295]

Answer:

1.6 + 1.6 + 1.6 + 3.1 = 7.9 miles walked

5 0

3 years ago

10! Or 10 factorial please