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ArbitrLikvidat [17]

3 years ago

7

What is the simplified form of squared root 140?

2 answers:

kompoz [17]3 years ago

6 0

Its 2 square root of 35

irga5000 [103]3 years ago

6 0

ANSWERS to Algebra 1 B Unit 5: Radical Expressions and Data Analysis

1. D

2. B

3. A

4. B

5. D

100% correct 5/5

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There are 15 female performers in a dance recital. The ratio of men to women is 2:3. How many men are in the dance recital?

andre [41]

If 3 represents women, then we divide 15 by 3 to get 5. once we have 5, we must then multiply 2 and 5. once that is done we have 10. So the number of men in the dance recital is 10.

Hope this answer helps! feel free to ask any additional questions :)

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This rectangle is half as wide as it is long what is the perimeter of the rectangle

kramer

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What is 10000 more than 46952 and what is the missing<br> number

Morgarella [4.7K]

10000 more than 46952 is 56952

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3 years ago

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WITCHER [35]

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Step-by-step explanation:

4 0

3 years ago

The dye dilution method is used to measure cardiac output with 3 mg of dye. The dye concentrations, in mg/L, are modeled by c(t)

Lemur [1.5K]

Answer:

Cardiac output: $F=0.055 L\s$

Step-by-step explanation:

Given : The dye dilution method is used to measure cardiac output with 3 mg of dye.

To Find : Find the cardiac output.

Solution:

Formula of cardiac output: $F=\frac{A}{\int\limits^T_0 {c(t)} \, dt}$ ---1

A = 3 mg

$\int\limits^T_0 {c(t)} \, dt =\int\limits^{10}_0 {20te^{-0.06t}} \, dt$

Do, integration by parts

$[\int{20te^{-0.6t}} \, dt]^{10}_0=[20t\int{e^{-0.6t} \,dt}-\int[\frac{d[20t]}{dt}\int {e^{-0.6t} \, dt]dt]^{10}_0$

$[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-20te^{-0.6t}}{0.6}+\frac{20}{0.6}\int {e^{-0.6t} \,dt]^{10}_0$

$[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-20te^{-0.6t}}{0.6}+\frac{20e^{-0.6t}}{(0.6)^2}]^{10}_{0}$

$[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-200e^{-6}}{0.6}+\frac{20e^{-6}}{(0.6)^2}]+\frac{20}{(0.60^2}$

$[\int{20te^{-0.6t}} \, dt]^{10}_0=\frac{20(1-e^{-6}}{(0.6)^2}-\frac{200e^{-6}}{0.6}$

$[\int{20te^{-0.6t}} \, dt]^{10}_0\sim {54.49}$

Substitute the value in 1

Cardiac output: $F=\frac{3}{54.49}$

Cardiac output: $F=0.055 L\s$

Hence Cardiac output: $F=0.055 L\s$

4 0

2 years ago