Answer:
28.27
you just have to know the formula
You're just a step away from the equation of the line that's perpendicular to [ y = 5/6 x + 7 ]. ... You know that its slope is -6/5 and that it contains the point (3, 2). ... Find the equation of that line. Then find the point where the two lines intersect. Then find the distance between that point and (3, 2). SIR !
Answer:
Step-by-step explanation:
\[2~ sin^2 x+3sin x+1=0\]
\[2sin^2x+2sin x+sin x+1=0\]
2sinx(sin x+1)+1(sin x+1)=0
(sin x+1)(2 sin x+1)=0
either sin x+1=0
sin x=-1=sin 3π/2=sin (2nπ+3π/2)
x=2nπ+3π/2,where n is an integer.
or 2sin x+1=0
sin x=-1/2=-sin π/6=sin (π+π/6),sin (2π-π/6)=sin (2nπ+7π/6),sin (2nπ+11π/6)
x=2nπ+7π/6,2nπ+11π/6,
where n is an integer.
