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3 years ago

Use the frequency table to determine how many students received a score of 70 or better on an English exam.

Mathematics

1 answer:

lesantik [10]3 years ago

7 0

Answer: 15 students

Step-by-step explanation:

>70= 5+6+4 students

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8. The difference between two numbers is 14. If 1/3of the larger number is subtracted from the smaller number, the

Serjik [45]

Answer:

The values of the 2 numbers whose sum is 13 and difference is 3, are: {8 ; 5}.

Step-by-step explanation:

7 0

3 years ago

Y - (z + z); y = 10, z =2

DiKsa [7]

The answer is 6. You just have to replace the values and done.

3 0

3 years ago

Read 2 more answers

A farmer is building a fence to enclose a rectangular area consisting of two separate regions. The four walls and one additional

Vlad [161]

Answer:

The maximal area will be "1093.5 square feet".

Step-by-step explanation:

Let,

Length = L feet

Breadth = b feet

Given Total fencing = 162 feet

According to the question,

$(2\times L)+(3\times b)=162$

$2L+3B=162$

$L=\frac{162-3b}{2}$

$L=81-\frac{3}{2}b$

As we know,

$Area=Length\times breadth$

$=(81-\frac{3}{2}b)\times b$

$=81b-\frac{3}{2}b^2$

Now, we required to decrease or minimize the are. So for extreme points:

$\frac{dA}{db}=0$

or,

$\frac{dA}{dB}=\frac{d}{db}(81-\frac{3}{2}b^2 )=0$

$81-\frac{3}{2}\times 2\times b=0$

$b=\frac{81}{3}$

$b=27 \ feet$

Now on putting the value of b, we get

$l=81-\frac{3}{2}\times 27$

$=81-40.5$

$=40.5 \ feet\\$

So that the dimensions will be:

⇒ 40.5 feet by 27 feet

Therefore when the dimension are above then the area will be:

= $81\times 27-\frac{3}{2}\times 27\times 27$

= $2187-\frac{3}{2}\times 729$

= $2187-1093.5$

= $1093.5 \ square \ feet$

6 0

3 years ago

A car dealer sells four model types: A,B,C,D. On a given week, this dealer sold 10 cars of model A, 5 of model B, 8 of model C a

olasank [31]

Answer:

its latter A

Step-by-step explanation:

i hope its help

3 0

3 years ago

Can someone help me pls

docker41 [41]

Answer:

See below

Step-by-step explanation:

For seg FG to be tangent to the circle with center E, the side lengths 6, 10, 12 must follow the rule of Pythagorean triplets.

So,

${10}^{2} + {6}^{2} = 100 + 36 = 136 \\ \\ {12}^{2} = 144 \\ \\ \because \: {10}^{2} + {6}^{2} \neq \: {12}^{2} \\$

From above it is obvious that given segment lengths doesn't follow the Pythagorean triplet rule. Therefore, seg FG is not tangent to the circle with center E.

6 0

3 years ago