A-9 2/3 B-3 3/8 C-5 D-4 1/5
Exponentail thingies
easy, look at all them them, see that they have 5 in common?
rremember how esay it was to factor
ax^2+bx+c=0
now we have
5^(2x)-6(5^x)+5=0
remember that 5^(2x)=(5^2)^x or (5^x)^2
in other words, we can rewrite it as
1(5^x)^2-6(5^x)+5=0
if yo want, replace 5^x with a and factor
1a^2-6a+5=0
(a-1)(a-5)=0
a=5^x
(5^x-1)(5^x-5)=0
set each to zero
5^x-1=0
5^x=1
take the log₅ of both sides
x=log₅1
5^x-4=0
5^x=4
take the log₅ of both sides
x=log₅4
x=log₅1 and/or log₅4
second quesiton
same thing
1(2^x)-10(2^x)+16=0
factor
(2^x-8)(2^x-2)=0
set each to zero
2^x-8=9
2^x=8
x=3
2^x-2=0
2^x=2
x=1
x=3 or 1
first one
x=log₅1 and/or log₅4
second one
x=1 and/or 3
72y+108z Factored is 36(2y+3z). So I guess the 2 factors will be 2y and 3z??
Answer:
The quantity of acid in the solution is 47.1 ml
Step-by-step explanation:
Given as :
The quantity of solution of acid and water = 357 millimeters
The percentage of acid in the solution = 13.2 %
Let the quantity of acid in the solution = x ml
<u>So, According to question </u>
13.2 % of the total quantity of acid in the solution = x
I.e x = 13.2 % × 357
Or, x = 
× 357
Or, x = 0.132 × 357
∴ x = 47.124 millimeters
So , The quantity of acid = 47.1 ml
Hence The quantity of acid in the solution is 47.124 ml Answer
