All categories

4 years ago

Solve the equation x-3=23 X=

Mathematics

2 answers:

White raven [17]4 years ago

8 0

Answer:

Step-by-step explanation:

26 - 3 = 23

hope this helps

mart [117]4 years ago

7 0

Answer:

x = 26

Step-by-step explanation:

x-3=23

Add 3 to each side

x-3+3=23+3

x = 26

You might be interested in

Find the value of x if this is a rectangle.<br>

Bumek [7]

Answer:

$x=4$

Step-by-step explanation:

we know that

In a rectangle the two diagonals are congruent (same length), and each diagonal bisects the other.

In this problem

$(2x-1)=(x+3)$

solve for x

$(2x-x)=(3+1)$

$x=4$

4 0

4 years ago

8x + 2y =16<br>standard form <br>1) m=<br>2 y - intercept x - intercept <br>

mestny [16]

Answer:

m=-4

y-intercept=8

x-intercept=2

Step-by-step explanation:

Please see attachment.

y-intercept=8

The y-intercept is where the line crosses the y-axis.

x-intercept=2

The x-intercept is where the line crosses the x-axis.

m=-4

If you do not know how to find slope by looking at graph, use slope formula.

(y2-y1)/(x2-x1)

Choose 2 points. You may use the x and y intercepts.

(2,0) and (0,8)

(8-0)/(0-2)=8/-2=-4

Hope this helps!

5 0

2 years ago

Use arrow notation to describe the translation of point P(–9, 5) to point P′(–6, 7).

Andreyy89

$P(-9;\ 5);\ P'(-6;\ 7)\\\\x:-6-(-9)=-6+9=3\\y:7-5=2\\\\Answer:\\\\\boxed{c)\ (x;\ y)\to(x+3;\ y+2)}$

$x:x_{P'}-x_P\\\\y:y_{P'}-y_P$

7 0

4 years ago

If you are given the graph of g (x) = log Subscript 2 Baseline x, how could you graph f (x) = log Subscript 2 Baseline x + 5?

olganol [36]

<h3>Answer: Shift the graph of g(x) up 5 units</h3>

Reasoning:

$g(x) = \log_2(x)$

$f(x) = \log_2(x)+5$

We see that f(x) = g(x)+5. Whatever the output of g(x) is, we add on 5 to get the output of f(x). The input is x, while the output is y. Adding 5 to the y output is what shifts every point on g(x) up 5 units to move the entire curve up 5 units.

8 0

3 years ago

Read 2 more answers

If F(x) = f(x)g(x), where f and g have derivatives of all orders

user100 [1]

a. By the product rule,

$F=fg\implies F'=f'g+fg'$

$\implies F''=(f''g+f'g')+(f'g'+fg'')=f''g+2f'g'+fg''$

b. By the same rule,

$F'''=(f'''g+f''g')+2(f''g'+f'g'')+(f'g''+fg''')$

$F'''=f'''g+3f''g'+3f'g''+fg'''$

and

$F^{(4)}=(f^{(4)}g+f'''g')+3(f'''g'+f''g'')+3(f''g''+f'g''')+(f'g'''+fg^{(4)})$

$F^{(4)}=f^{(4)}g+4f'''g'+6f''g''+4f'g'''+fg^{(4)}$

c. You might recognize the coefficients as those that appear in the expansion of $(a+b)^n$ :

1, 1

1, 2, 1

1, 3, 3, 1

1, 4, 6, 4, 1

and so on; the general pattern (known as the general Leibniz rule) is

$F^{(n)}=\displaystyle\sum_{k=0}^n\binom nkf^{(n-k)}g^{(k)}$

6 0

3 years ago