Answer:
A
Step-by-step explanation:
surface area is solving for the entire surface. Thus, you find the area of the triangles and the square base.
A.)
<span>s= 30m
u = ? ( initial velocity of the object )
a = 9.81 m/s^2 ( accn of free fall )
t = 1.5 s
s = ut + 1/2 at^2
\[u = \frac{ S - 1/2 a t^2 }{ t }\]
\[u = \frac{ 30 - ( 0.5 \times 9.81 \times 1.5^2) }{ 1.5 } \]
\[u = 12.6 m/s\]
</span>
b.)
<span>s = ut + 1/2 a t^2
u = 0 ,
s = 1/2 a t^2
\[s = \frac{ 1 }{ 2 } \times a \times t ^{2}\]
\[s = \frac{ 1 }{ 2 } \times 9.81 \times \left( \frac{ 12.6 }{ 9.81 } \right)^{2}\]
\[s = 8.0917...\]
\[therfore total distance = 8.0917 + 30 = 38.0917.. = 38.1 m \] </span>
Avg of 7 numbers = 9
Total of 7 numbers will be = 9 * 7 = 63
Avg of 3 of them is = 5
Total of those 3 will be = 3 * 5 = 15
Therefore the total of other 4 = 63 - 15 = 48
Ergo , avg of them = 48 / 4 = 12
Answer is 12
hope this helps!
Answer:
x = 40
Step-by-step explanation:
Given 2 secants from an external point to the circle, then
The product of the external part and the whole of one secant is equal to the product of the external part and the whole of the other secant, that is
8(8 + x) = 12(12 + 20)
8(8 + x) = 12 × 32 = 384 ( divide both sides by 8 )
8 + x = 48 ( subtract 8 from both sides )
x = 40
