Answer:
Step-by-step explanation:
p=sec0+tan0
=1/cos0 + sin0/cos0
=(1+sin0)/cos0
square both sides
(1+sin)^2 /cos^2 = p^2
(1+sin)^2/(1 - sin^2 ) = p^2
(1+sin)^2/((1-sin)(1+sin)) = p^2
(1+sin)/(1-sin)=p^2
1+sin=p^2-p^sin
sin+p^2sin=p^2-1
sin(1+p^2)=(p^2-1)
sin=(1-p^2)/(1+p^2)
cosec=1/sin
=(1+p^2)/(1-p^2)
20 hope this helped <333333333333333333333
Answer:
B=D
Step-by-step explanation:
Wild guess because no context.
Answer:
Possible C:
(1 , 1 + 3sqrt(3))
(1 , 1 - 3sqrt(3))
Step-by-step explanation:
AB = 6 units
Midpoint of AB is (1,1)
C would be at x = 1
So, (1,y)
(y-1)² + (1+2)² = 6²
(y-1)² = 36 - 9
(y-1)² = 27
y - 1 = 3sqrt(3)
y - 1 = -3sqrt(3)
y = 1 + 3sqrt(3)
y = 1 - 3sqrt(3)
Find their gradients using the change in y coords divided by the change in x coords. once you have the gradients (or slopes), multiply them by eachother - if the product is (-1) then theyre perpdendicular, if not, they are either parallel or intersect at a point
