Answer: ![\bold{\dfrac{h^9}{g^9}}](https://tex.z-dn.net/?f=%5Cbold%7B%5Cdfrac%7Bh%5E9%7D%7Bg%5E9%7D%7D)
<u>Step-by-step explanation:</u>
The power rule is "multiply the exponents".
You must understand that the exponent of both h and g is 1.
Multiply 1 times 9 for both variables.
![\bigg(\dfrac{h}{g}\bigg)^9=\bigg(\dfrac{h^1}{g^1}\bigg)^9=\dfrac{h^{1\times 9}}{g^{1\times 9}}=\large\boxed{\dfrac{h^9}{g^9}}](https://tex.z-dn.net/?f=%5Cbigg%28%5Cdfrac%7Bh%7D%7Bg%7D%5Cbigg%29%5E9%3D%5Cbigg%28%5Cdfrac%7Bh%5E1%7D%7Bg%5E1%7D%5Cbigg%29%5E9%3D%5Cdfrac%7Bh%5E%7B1%5Ctimes%209%7D%7D%7Bg%5E%7B1%5Ctimes%209%7D%7D%3D%5Clarge%5Cboxed%7B%5Cdfrac%7Bh%5E9%7D%7Bg%5E9%7D%7D)
Answer:
158.428571429
158 remainder 6
Step-by-step explanation:
Which two numbers add up to -80 and multiply to -81?
-81 and 1
Rewrite the expression using the above
(x^4 - 81)(x^4 + 1)
Rewrite x^4 - 81 in the form; a^2 - b^2, where a = x^2 and b = 9
((x^2)^2 - 9^2)(x^4 + 1)
Use the Difference of Squares: a^2 - b^2 = (a + b)(a - b)
(x^2 + 9)(x^2 - 9)(x^4 + 1)
Rewrite x^2 - 9 in the form a^2 - b^2, where a = x and b = 3
(x^2 + 9)(x^2 - 3^2)(x^4 + 1)
Use the Difference of Squares; a^2 - b^2 = (a + b)(a - b)
<u>(x^2 + 9(x + 3)(x - 3)(x^4 + 1)</u>