the smallest integer is 15
note that consecutive integers have a difference of 1 between them
let the smallest integer be n
then : n, n+ 1, n + 2, n + 3, n + 4, n + 5, n + 6
are seven consecutive integers with n + 6 being the largest, thus summing gives
7n + 21 = 6(6 + n)
7n + 21 = 36 + 6n ( distributing right side )
7n - 6n + 21 = 36 ( subtracting 6n from both sides )
n + 21 = 36 ⇒ n = 36 - 21 = 15
the smallest integer is 15
Answer:
I have to say, I was a bit stumped on this one for some reason, but I believe your answer is y^2.
Step-by-step explanation:
All four variables , (14, 15, y^2, & y^4) should all have a common denominator, but I only see similarities in y^2 with y^4 and 14 with 15, but the y's can be understood ones. Multiply your common variables and get y^2. Could someone check me in that though?
Answer:
a is the answer
Step-by-step explanation:
just find the square root of 16 which is four
there is no negative so that takes the other two out of it and it can be factored