I have seen this question before and I think you meant 10 more dimes than nickels.
We can use substitution to answer this question. The value of a nickel is 5 cents, and we can use the variable n to represent the number of nickels. The value of a dime is 10 cents, and we can use the variable d to represent the number of dimes.
First lets figure out the equations.
.10d+.5n=2.80 (the number of nickels (n) multiplied by .5 will tell us their money value. Same thing for the dimes)
d-n=10 (since there are 13 more dimes than nickels, the number of dimes value (d) minus the number of nickels value (n) will give us 10)
Now lets isolate a variable in one of the equations, preferably the second one because it doesn't have any visible coefficients,
d-n=10
-n=10-d (subtracted the d from both sides)
n=-10+d (made the n positive)
Now that we have the value of n, we can plug it into the other equation.
.10d+.05n=2.80
.10d+.05(-10+d)=2.80 (we replaced the n with the value that we previously got)
.10d-.5+.05d=2.80 (did the multiplication)
.15d-.5=2.80 (combined like terms)
.15d=3.30 (added the .5 to both sides)
d=22 (divided both sides by the .15)
Now that we know that there are 22 dimes and we also know that there are 10 less nickels than dimes, so we can subtract 10 from 22 to get the number of nickels. 22-10=12
d=22
n=12
I personally don’t know the answer so i can’t help
Answer:
see explanation
Step-by-step explanation:
The sum of the 3 angles in a triangle = 180°
sum the 3 angles and equate to 180
5x + 7 + 4x + 2 + 90 = 180 , that is
9x + 99 = 180 ( subtract 99 from both sides )
9x = 81 ( divide both sides by 9 )
x = 9
Then
∠ ACB = 4x + 2 = 4(9) + 2 = 36 + 2 = 38°
∠ BAC = 5x + 7 = 5(9) + 7 = 45 + 7 = 52°
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Since the triangles are congruent then corresponding angles are congruent , so
∠ B = ∠ E
6x + 10 = 70 ( subtract 10 from both sides )
6x = 60 ( divide both sides by 6 )
x = 10
Answer:
Domain: (-∞, ∞)
Range: [0, ∞)
Step-by-step explanation:
The domain represents what x can be. In this scenario, we do not have x as a denominator, and there is nothing limiting x, so its domain is (-∞, ∞)
The range represents what f(x) can be, Because |x-4| is in absolute value, the lowest |x-4| can be is 0, and as a result, the lowest value of 2|x-4| is 2*0=0. The maximum value of f(x) is ∞ as an absolute value does not limit the maximum, making the range [0, ∞)
