Answer:
In parallelogram ABCD
FD is perpendicular to BC
BE is perpendicular to CD
Consider triangle BEC and triangle DFC
FC = EC (Given)
Angle BEC = Angle DFC (=90°)
Angle BCE = Angle DCF (common)
Therefore triangle BEC is congruent to triangle DFC (AAS congruency)
DF = BE (CPCT)
Since the altitudes are equal their bases will also be equal
Therefore BC = DC
Therefore BC = DC = AD = AB
Therefore ABCD is a rhombus
Hope this helps!
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Answer: I believe those would be opposite angles (aka vertically opposite angles).
Answer:
46
Step-by-step explanation:
p=40+0.15(40)
=40+6
Answer:
c=42
s=30
Step-by-step explanation:
Answer:
5 days
Step-by-step explanation:
If you write it out it will look like this 8 1/2÷1 7/10
since you can't divide mixed fractions very easily, you make them improper fractions. 8 1/2 -> 17/2 1 7/10 -> 17/10
So it looks like 17/2÷17/10
because of maths you have to turn 17/10 into 10/17
And when you do the maths (multiply it together) you get 5
