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MrMuchimi
2 years ago
13

George desposited 2000 in his bank, which offers 5% compoud interest annually. What would be the principla amount available in g

eorges account at the and of two years
Mathematics
1 answer:
Tamiku [17]2 years ago
4 0
George would have 2200
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Red =18
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let orange = X and solve the equation
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2 years ago
Express the confidence interval 0.555 less than 0.777 in the form Modifying above p with caret plus or minus Upper E.
Elina [12.6K]

Complete Question

Express the confidence interval 0.555 less than p less than  0.777 in the form Modifying above p with caret plus or minus Upper E.

Answer:

The modified representation is \r p \pm  E  = 0.666 \pm  0.111

Step-by-step explanation:

From the question we are told that

    The  confidence interval interval is  0.555 <  p <  0.777

Now looking at the values that make up  the up confidence interval we see that this is a symmetric  confidence interval(This because the interval covers 95%  of the area under the normal curve which mean that the probability of a value falling outside the interval is 0.05 which is divided into two , the first half on the left -tail and the second half on the right tail  as shown on the figure in the first uploaded image(reference - Yale University ) ) which means

     Now  since the confidence interval is  symmetric , we can obtain the sample proportion as follows

             \r p  =  \frac{0.555 + 0.777}{2}

            \r p  =0.666

Generally the margin of error is mathematically represented as

            E  =  \frac{1}{2}  *  K

Where  K is the length of the confidence interval which iis mathematically represented as

           K  =  0.777 -0.555

         K  = 0.222

Hence  

          ME  =  \frac{1}{2}  *  0.222

           ME  =  0.111

So the confidence interval can now be represented as

        \r p \pm  E  = 0.666 \pm  0.111

     

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3 years ago
-2x + 3y = 1
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Answer:

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y=3x-9........(2)

Now,

putting the value of y in equation (1),

-2x+3(3x-9)=1

or,-2x+9x-27=1

or,7x-27=1

or,7x=28

x= 4

Now putting the value of X in equation (2),

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2 years ago
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Step-by-step explanation:

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