\left[x _{2}\right] = \left[ \frac{-1+i \,\sqrt{3}+2\,by+\left( -2\,i \right) \,\sqrt{3}\,by}{2^{\frac{2}{3}}\,\sqrt[3]{\left( 432\,by+\sqrt{\left( -6912+41472\,by+103680\,by^{2}+55296\,by^{3}\right) }\right) }}+\frac{\frac{ - \sqrt[3]{\left( 432\,by+\sqrt{\left( -6912+41472\,by+103680\,by^{2}+55296\,by^{3}\right) }\right) }}{24}+\left( \frac{-1}{24}\,i \right) \,\sqrt{3}\,\sqrt[3]{\left( 432\,by+\sqrt{\left( -6912+41472\,by+103680\,by^{2}+55296\,by^{3}\right) }\right) }}{\sqrt[3]{2}}\right][x2]=⎣⎢⎢⎢⎢⎡2323√(432by+√(−6912+41472by+103680by2+55296by3))−1+i√3+2by+(−2i)√3by+3√224−3√(432by+√(−6912+41472by+103680by2+55296by3))+(24−1i)√33√(432by+√(−6912+41472by+103680by2+55296by3))⎦⎥⎥⎥⎥⎤
totally answer.
Answer:
Step-by-step explanation:
we have that
The scale drawing is
we know that
Using proportion find out the actual dimensions of the volleyball court
Let
x -----> drawing court lengths in cm
y ----> court lengths in cm
For x=40 cm
For x=80 cm
Find the equation for the proportional relation ship between drawing court lengths x in centimeters and court lengths in y centimeters
A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form 
or 
For x=40 cm, y=900
substitute
-----> 
The equation is
Step-by-step explanation:
21:18=7:6
42:36=7:6
63:54=7:6
Answer:
281/2/5 miles
Step-by-step explanation:
469/5 = 93.8
93.8x3 = 281.4
= 281/2/5 miles
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Answer:
12.3
Step-by-step explanation:
You will use cosine to solve for y because you are given the hypontenuse and need to find the adjacent side.
cos 35 degrees = adjacent/hypontenuse
cos 35 = y/ 15
15( cos35 ) = y
y=12.287
=12.3
