Please help me with some of the questions

Áp dụng quy tắc khai phương 1 tích hãy tính

Zinaida [17]

Answer:

Please write out in english

Step-by-step explanation:

I cannot help unless you can translate.

6 0

3 years ago

HJ= 5x -3, JK= 8x -9 and KH= 131

Fynjy0 [20]

Answer:

HJ = 52

JK = 79

Step-by-step explanation:

Hello, I want to assume you are trying to determine either HJ or JK. Below is an illustration of how to determine either HJ or JK.

From the question given above, the following data were obtained:

HJ = 5x – 3

JK = 8x – 9

KH = 131

If we draw a straight line, we'll observe the following:

H_______J_______K

KH = HJ + JK

Next, we shall determine the value of x.

HJ = 5x – 3

JK = 8x – 9

KH = 131

KH = HJ + JK

131 = (5x – 3) + (8x – 9)

131 = 5x – 3 + 8x – 9

Collect like terms

131 + 3 + 9 = 5x + 8x

143 = 13x

Divide both side by 13

x = 143 / 13

x = 11

Finally, we shall determine HJ and JK. This can be obtained as follow:

For HJ:

HJ = 5x – 3

x = 11

HJ = 5(11) – 3

HJ = 55 – 3

HJ = 52

For JK:

JK = 8x – 9

x = 11

JK = 8x – 9

JK = 8(11) – 9

JK = 88 – 9

JK = 79

6 0

4 years ago

I'm totally lost please help i have a test on it tomorrow

Mumz [18]

If the pattern continues, it could be 2.75 * 63.63 repeating to get to the end of the card. The second answer is 63. When she started the card, she had $175. Divide 175 by 2.75 and you get 63 repeating.

3 0

3 years ago

Question set 1: One instructor believes that students take more than 2 classes per quarter on average. He randomly interviewed a

Sveta_85 [38]

Answer:

There is statistical evidence at 95% level to claim that students attend more than 2 classes per quarter

Step-by-step explanation:

Given that one instructor believes that students take more than 2 classes per quarter on average. Let X be the no of classes students take.

$H_0: \bar x =2\\H_a: \bar x >2$

(Right tailed test at 5% significance level)

$\bar x =2,3 \\s = 0.8$

Mean difference = $2.3-2=0.3$

Std error = $\frac{0.8}{\sqrt{24} } \\=0.1633$

Test statistic t = mean diff/std error = 1.84

p value =0.039

Since p <0.05, we reject null hypothesis.

There is statistical evidence at 95% level to claim that students attend more than 2 classes per quarter

3 0

4 years ago

Use the appropriate substitutions to write down the first four nonzero terms of the Maclaurin series for the binomial (1+3x)^(-1

PolarNik [594]

Answer:

First term=1

Second term=-x

Third term= $2x^2$

Fourth term = $-\frac{28}{3!}x^3$

Step-by-step explanation:

We are given that function

$f(x)=(1+3x)^{-1/3}$

We have to find the first four non zero terms of the Maclaurin series for the binomial.

Maclaurin series of function f(x) is given by

$f(x)=f(0)+f'(0)x+\frac{1}{2!}f''(0)x^2+\frac{1}{3!}f'''(0)x^3+....$

$f(0)=(1+3x)^{\frac{-1}{3}}=1$

$f'(x)=-\frac{1}{3}(1+3x)^{-\frac{4}{3}}(3)=-(1+3x)^{-\frac{4}{3}}$

$f'(0)=-1$

$f''(x)=\frac{4}{3}\times 3 (1+3x)^{-\frac{7}{3}}$

$f''(0)=4$

$f'''(x)=-4\times \frac{7}{3}\times 3(1+3x)^{-\frac{10}{3}}$

$f'''(0)=-28$

Substitute the values we get

$(1+3x)^{-\frac{1}{3}}=1-x+\frac{4}{2!}x^2+\frac{-28}{3!}x^3+...$

$(1+3x)^{-\frac{1}{3}}=1-x+2x^2+\frac{-28}{3!}x^3+...$

First term=1

Second term=-x

Third term= $2x^2$

Fourth term = $-\frac{28}{3!}x^3$

5 0

3 years ago