Answer:
It is definitenly B)60
Step-by-step explanation:
Answer:
A (2/8)
HOPE YOU WILL LIKE MY ANSWER
He area of an equilateral triangle of side "s" is s^2*sqrt(3)/4. So the volume of the slices in your problem is
<span>(x - x^2)^2 * sqrt(3)/4. </span>
<span>Integrating from x = 0 to x = 1, we have </span>
<span>[(1/3)x^3 - (1/2)x^4 + (1/5)x^5]*sqrt(3)/4 </span>
<span>= (1/30)*sqrt(3)/4 = sqrt(3)/120 = about 0.0144. </span>
<span>Since this seems quite small, it makes sense to ask what the base area might be...integral from 0 to 1 of (x - x^2) dx = (1/2) - (1/3) = 1/6. Yes, OK, the max height of the triangles occurs where x - x^2 = 1/4, and most of the triangles are quite a bit shorter...
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Answer:
The answer is 13, 9 and (-1)
Step-by-step explanation:
<h3><u>Given</u>;</h3>
<h3><u>To </u><u>Find</u>;</h3>
- h(x) = (-2x + 9) when x = (-2), 0 and 5.
For x = (-2)
h(x) = (-2x + 9)
h(-2) = [-2(-2) + 9]
h(-2) = (4 + 9)
h(-2) = 13
For x = 0
h(x) = (-2x + 9)
h(0) = [-2(0) + 9]
h(0) = (0 + 9)
h(0) = 9
For x = 5
h(x) = (-2x + 9)
h(5) = [-2(5) + 9]
h(5) = [(-10) + 9]
h(5) = (-1)
Thus, The answer is 13, 9 and (-1) when x = (-2), 0 and 5 respectively.
Answer: x>-2
explanation: = -4x<8
= -4x/(-4)>8/(-4)
= x>-2