Can you help pls jhgyihjopk[[knbh
2 answers:
Answer:
The lower right table
Step-by-step explanation:
The table of that's the right answer consists of f(x) and x points that when plugged into the equation make the equation equal.
Let's go through each of the tables to check.
Upper Left Table:
(Remember that f(x) and y are interchangeable)
- Let's plug in the first paired set (0,6) into the equation
So, this one seems right so far. It also let's us eliminate some answers!
The upper right and lower left tables can't be right because in order for the equation to be equal, f(x) has to be 6 when x equals 0
Let's plug more paired sets into the equation from the upper left table
This doesn't work so let's check to see if the lower right table is correct!
Since the equation is equal, this has to be the right answer!
<em>Hope this helps!!</em>
<em>- Kay</em>
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We know that
(ad)/(bd)=d/d time a/b=a/b since d's cancel
also
if a/b=c/d in simplest form, then a=c and b=d
we have
p/(x^2-5x+6)=(x+4)/(x-2)
therefor
p/(x^2-5x+6)=d/d times (x+4)/(x-2)
p/(x^2-5x+6)=d(x+4)/d(x-2)
therefor
p=d(x+4) and
x^2-5x+6=d(x-2)
we can solve last one
factor
(x-6)(x+1)=d(x-2)
divide both sides by (x-2)
[(x-6)(x+1)]/(x-2)=d
sub
p=d(x+4)
p=([(x-6)(x+1)]/(x-2))(x+4)
(ad)/(bd)=d/d time a/b=a/b since d's cancel
also
if a/b=c/d in simplest form, then a=c and b=d
we have
p/(x^2-5x+6)=(x+4)/(x-2)
therefor
p/(x^2-5x+6)=d/d times (x+4)/(x-2)
p/(x^2-5x+6)=d(x+4)/d(x-2)
therefor
p=d(x+4) and
x^2-5x+6=d(x-2)
we can solve last one
factor
(x-6)(x+1)=d(x-2)
divide both sides by (x-2)
[(x-6)(x+1)]/(x-2)=d
sub
p=d(x+4)
p=([(x-6)(x+1)]/(x-2))(x+4)