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8090 [49]
3 years ago
13

Simplify the following fraction:

id="TexFormula1" title="\frac{(x+2)^2+3(x+2)^2}{x^2-4}" alt="\frac{(x+2)^2+3(x+2)^2}{x^2-4}" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
dlinn [17]3 years ago
6 0

The answer is \frac{4(x+2)}{x-2}. Reason is becasue you simplify it, making it \frac{4(x+2)}{x-2}. How do we get this? Add similar elements of the numerator equation (the numerator on your question), making it \frac{4(x+2)}{x^2-2}. Then x^2 - 4 would be the step, "apply difference of two squares formula," giving us (x+2)(x-2). Now we cancel the common factor, which is x + 2, giving us the answer that I gave you in the first sentence, \frac{4(x+2)}{x-2}.

Hope this helped!

Nate

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