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3 years ago

How to find variables x- and y-

Mathematics

1 answer:

Monica [59]3 years ago

5 0

It says that the triangles are congruent (same size). Also, a triangle's angles add up to 180 degrees. In both of these triangles, one angle is 90° and another angle is 52°. The other angle is 180°-90°-52°=38°.

Solve these equations to find x and y: 2x+18=38, 3y+11=38

$2x+18=38\\2x=20\\x=10$

$3y+11=38\\3y=27\\y=9$

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One 3.8 lb bag of fertilizer covers 1000 square feet each bag cost $9.95 the square feet of the yard is 1307.25 ft squared how m

zaharov [31]

Answer:

Exactly 1.30725 bags are needed to cover the garden.

Step-by-step explanation:

We have a yard with a surface of 1307.25 square feet.

We know that one bag of fertilizer covers 1000 square feet.

We want to know how many bags are needed to cover the garden. We can calculate the number of bags as:

$B=S\cdot b=1307.25\;\text{sq.ft.}\cdot \dfrac{1\,\text{bag}}{1000\,\text{sq.ft.}}=1.30725\,\text{bags}$

B: number of bags needed for the yard.

S: surface of the yard.

b: number of bags per square foot.

4 0

4 years ago

Please help, Using The graph answer the following questions

ELEN [110]

Answers:

1. (2,0)
2. 0
3. 1

5 0

3 years ago

My last question plz help me

LenKa [72]

The answer is c I hope this helps

4 0

3 years ago

Read 2 more answers

The volume of a sphere is 113.04 cubic feet. Find the radius. Use 3.14 for pi.

avanturin [10]

Volume is 4/3(3.14)(r)^2
the radius is 5.2 ft

4 0

3 years ago

Hello can someone help me simplify 4) and 5)? Thank you and please include steps :)

Leni [432]

Alrighty

remember some rules
$(ab)^c=(a^c)(b^c)$
and
$x^{-m}=\frac{1}{x^m}$
and
$x^0=1$ for all real values of x
and
$(a^b)^c=a^{bc}$
and
$(\frac{a}{b})^c=\frac{a^c}{b^c}$
and
(a/b)/(c/d)=(ad)/(bc)
and
$(a^b)(a^c)=a^{b+c}$
and
$\frac{a^m}{a^n}=a^{m-n}$
and don't forget pemdas
example: $-x^m=-1(x^m)$ but $(-x)^m=(-1)^m(x^m)$

so

4.
$(\frac{c^{-2}}{2})^{-2}=$

$\frac{(c^{-2})^{-2}}{2^{-2}}=$

$\frac{c^4}{\frac{1}{2^2}}=$

$\frac{c^4}{\frac{1}{4}}=$

$4c^4$

5.

$\frac{(-a)^4bc^5}{-a^2b^{-3}c^0}=$

$\frac{(-1)^4(a)^4bc^5}{-1(a^2)(\frac{1}{b^3}(1)}=$

$\frac{(1)a^4bc^5}{\frac{(-1)(a^2)}{b^3}}=$

$\frac{(a^4bc^5)b^3}{(-1)(a^2)}=$

$\frac{-a^4b^4c^5}{a^2}=$

$-a^2b^4c^5$

3 0

3 years ago