The one on the left is b and the one on the right is -1.
Answer:
105+15=3x
120=3x
x=40
be grateful, I don't help ppl usually
There are thirty seven seats in total.
Answer:
Step-by-step explanation:
Okay, so I think I know what the equations are, but I might have misinterpreted them because of the syntax- I think when you ask a question you can use the symbols tool to input it in a more clear way, otherwise you can use parentheses and such.
Problem 1:
(x²)/4 +y²= 1
y= x+1
*substitute for y*
Now we have a one-variable equation we can solve-
x²/4 + (x+1)² = 1
x²/4 + (x+1)(x+1)= 1
x²/4 + x²+2x+1= 1
*subtract 1 from both sides to set equal to 0*
x²/4 +x^2+2x=0
x²/4 can also be 1/4 * x²
1/4 * x² +1*x² +2x = 0
*combine like terms*
5/4 * x^2+2x+ 0 =0
now, you can use the quadratic equation to solve for x
a= 5/4
b= 2
c=0
the syntax on this will be rough, but I'll do my best...
x= (-b ± √(b²-4ac))/(2a)
x= (-2 ±√(2²-4*(5/4)*(0))/(2*(5/4))
x= (-2 ±√(4-0))/(2.5)
x= (-2±2)/2.5
x will have 2 answers because of ±
x= 0 or x= 1.6
now plug that back into one of the equations and solve.
y= 0+1 = 1
y= 1.6+1= 2.6
Hopefully this explanation was enough to help you solve problem 2.
Problem 2:
x² + y² -16y +39= 0
y²- x² -9= 0
Answer:
No solution
Step-by-step explanation:
-3x + 3y = 4
-x + y = 3
<u>Solve the equation for x:</u>
<u>Move the variable to the right side and change its sign</u>
-x + y = 3
-x = 3 - y
<u>Change the signs on both sides of the equation</u>
-x = 3 - y
x = -3 + y
<u>Substitute the given value of x into the equation -3x + 3y = 4</u>
-3x + 3y = 4
x = -3 + y
-3(-3+y)+3y=4
<u>Solve the equation for y</u>
-3(-3+y)+3y=4
y = 0
There is no solution for y.
And since there's no solution for y, the system has no solution.
