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masya89 [10]
3 years ago
15

In 2005 Richard earned £22,000 per year.

Mathematics
1 answer:
Slav-nsk [51]3 years ago
6 0
It’s 45%

Explanation = 31900-22000/22000 • 100 = 45%
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Question
AlekseyPX

Answer:

The population mean is 5 volts

Step-by-step explanation:

Output voltage is assumed to be normally distributed, with standard deviation 0.25 Volts

s=0.25

n = 8

H_0:\mu = 5\\H_a:\mu \neq 5

Sample mean = \bar{x}=4.85

Since n < 30 and population standard deviation is unknown

So, we will use t test

Formula : t = \frac{x-\mu}{\frac{s}{\sqrt{n}}}

t = \frac{4.85-5}{\frac{0.25}{\sqrt{8}}}

t=-1.69

Refer the t table for p value

Degree of freedom = n-1 = 8-1 = 7

So,t_{(df,\alpha)}=t_{7,0.05}=2.365

P value >α

So, We are failed to reject null hypothesis

Hence The population mean is 5 volts

7 0
4 years ago
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ollegr [7]

Answer:

The scale factor is 4

Step-by-step explanation:

Divide one of the sides on the larger shape with the corresponding side on the smaller shape. So if you choose the top one you would to 40/10 which is 4.

3 0
4 years ago
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The table shows the party affiliation of 100 senators. The ratio of Republicans to Democrats is 5 : 4. How many senators are Ind
kow [346]

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Step-by-step explanation:

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3 years ago
A random sample of 10 observations was selected from a normal population distribution. The sample mean and sample standard devia
Delvig [45]

Answer:

18.0167≤x≤21.9833

Step-by-step explanation:

Given the following

sample size n = 10

standard deviation s = 3.2

Sample mean = 20

z-score at 95% = 1.96

Confidence Interval = x ± z×s/√n

Confidence Interval = 20 ± 1.96×3.2/√10

Confidence Interval = 20 ± (1.96×3.2/3.16)

Confidence Interval = 20 ± (1.96×1.0119)

Confidence Interval = 20 ±  1.9833

CI = {20-1.9833, 20+1.9833}

CI = {18.0167, 21.9833}

Hence the required confidence interval is 18.0167≤x≤21.9833

8 0
3 years ago
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OLga [1]

Answer:

boo boo bbababababababyguewjskk34ihuewoudhhun.b odcb p;dwqvul wqionwqvgkwxdb ;qwdStep-by-step explanation:

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4 years ago
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