a rectangle has a length of 10 ft. and a width of 6 ft. what's the perimeter? a. 60 ft. b. 16 ft. c. 32 ft. d. 26 ft.

Mathematics

2 answers:

Veronika [31]2 years ago

8 0

32 because you add all the out side lengths

kow [346]2 years ago

7 0

Answer: The required perimeter of the rectangle is 32 ft.

Step-by-step explanation: Given that a rectangle has a length of 10 ft. and a width of 6 ft.

We are to find the perimeter of the rectangle.

We know that

the perimeter of a rectangle with length l units and width w units is given by

$P=2(l+w).$

For the given rectangle, we have

length, l = 10 ft. and width, w = 6 ft.

Therefore, the perimeter of the rectangle is

$P=2(l+w)=2(10+6)=2\times16=32.$

Thus, the required perimeter of the rectangle is 32 ft.

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On a bicycle trail, the city is painting arrows like the one shown below: Upper pointing arrow with height of 15 and length of 1

Luden [163]

Answer:

229.5 $cm^{2}$

Step-by-step explanation:

In order to calculate the area of the arrow we need to calculate the area of the body of the arrow, and then the head of the arrow. The body of the arrow is a rectangle meaning that the area (Ar) can be calculated by multiplying the length by the height like so...

Ar = l * h

Ar = 11cm * 12cm

Ar = 132 $cm^{2}$

Now we need to find the area of the head of the arrow, which is a triangle and therefore we can use the formula for the area of a triangle (At) which is height times base divided by 2...

At = $\frac{h * b}{2}$