Question

a rectangle has a length of 10 ft. and a width of 6 ft. what's the perimeter? a. 60 ft. b. 16 ft. c. 32 ft. d. 26 ft.

Answer 1

32 because you add all the out side lengths

Answer 2

Answer:  The required perimeter of the rectangle is 32 ft.

Step-by-step explanation:  Given that a rectangle has a length of 10 ft. and a width of 6 ft.

We are to find the perimeter of the rectangle.

We know that

the perimeter of a rectangle with length l units and width w units is given by

$P=2(l+w).$

For the given rectangle, we have

length, l = 10 ft.  and  width, w = 6 ft.

Therefore, the perimeter of the rectangle is

$P=2(l+w)=2(10+6)=2\times16=32.$

Thus, the required perimeter of the rectangle is 32 ft.