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2 years ago

Geometry help asap please

Mathematics

1 answer:

NemiM [27]2 years ago

5 0

Answer:

99 degrees

Step-by-step explanation:

81+a=180, so

180-81=99

a=99

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whole milk is 4% butterfat how much skim milk with 0% butterfat should be added to 32 ounces of whole milk to obtain a mixture t

vivado [14]

Answer:

whole milk 4 ---------------- 32 ounces

skim milk 0 ---------------- x ounces

Mixture 2.5 ---------------- 32 + x ounces

4*32+0x =2.5(32 +x)

128+0x= 80+2.5 x

0 x + -2.5 x = 80 - -128

-2.5 x = -48

/ -2.5

x = 19.2

19.2 ounces of 0 % fat skim milk

4 0

2 years ago

If Brenda has 10 math problems to solve and she can solve one math problem per minute how long will it take her to solve all 10

Nina [5.8K]

Answer:she will take 10 minutes

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

stira [4]

Answer:

Step-by-step explanation:

Set up as a proportion:

$\frac{QR}{QP}=\frac{BA}{BC}$ , insert given values

$\frac{?}{12}=\frac{30}{36}$ , cross multiple

36*?=30*12

36*?=360, divide both sides by 36 to get the missing side (?) by itself

?=10

3 0

2 years ago

☺WILL MARK BRAINLIEST IF YOU GIVE THE RIGHT ANSWER☺

RoseWind [281]

Simple.
Plug in what you known into the equation.
150 = 6e^2.
Divide 150 by 6 to isolate the variable.
150/6 = e^2
25 = e^2
take the square root of 25
5 = e

Hope this helps!

4 0

2 years ago

Six human skulls from around 4000 b.c. were measured, and the lengths have a mean of 94.2 mm and a standard deviation of 4.9

professor190 [17]

Answer:

Step-by-step explanation:

Hello!

You have to estimate the mean length of 4000 b.c. human skulls trough a 95% confidence interval.

You know that

n= 6 human skulls

$\frac{}{X}$ = 94.2mm

S= 4.9

Assuming that the variable X: length of a 4000b.c. human skull (mm) has a normal distribution, to construct the interval you have to use the t statistic:

[ $\frac{}{X}$ ± $t_{n_1;1-\alpha /2} * \frac{S}{\sqrt{n} }$ ]

$t_{n-1;1-\alpha /2}= t_{5; 0.975}= 2.571$

[94.2 ± 2.571 * $\frac{4.9}{\sqrt{6} }$ ]

[89.06; 99.34]mm

With a 95% confidence level you'd expect the interval [89.06; 99.34]mm to contain the value for the average skull length for humans 4000 b.c.

I hope this helps!

3 0

3 years ago