The ball's maximum height is 30.25 feet.
<h3>What is quadratic equation?</h3>
A quadratic equation in math is a second-degree equation of the form ax² + bx + c = 0. Here a, b, are the coefficients, c is the constant term, and x is the variable.
Given:
h= -16t²+36t+10
Differentiate w.r.t. 't',
h' = -32t+36
When h=0, that will be the maximum height
32t= 36
t= 9/8
t= 1.125 sec.
So, The maximum height is
h(1.123)= -16(1.125)² + 36*1.125+10
h(1.125) = 30.25 feet.
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Answer and working out attached below. Hope it helps
Answer:
What do you need help with? Answer and I will tell you anything you need.
Step-by-step explanation:
Cos (x) = adj/hyp
cos (x) = 13/25
x = cos⁻¹(13/25)
x= 58.7° (nearest tenth)
The product will be 2x^2 + 5x - 3