All categories

3 years ago

Seth traveled 1 mile in 57.1 seconds. About how fast does Seth travel in mph?

2 answers:

6 0

Considering that Seth travels with constant speed v=dtv=dt, then v=157.1=x3600v=157.1=x3600 where xx is the distance traveled in 1 hour. So his velocity would be x miles/hour. By computing x=3600⋅157.1=63.047x=3600⋅157.1=63.047, thus Seth travels at a speed of 63.047miles/hour63.047miles/hour

charle [14.2K]3 years ago

5 0

The answer is 760 mph

You might be interested in

Nine times the difference of a number and 4 is the same as the product of 2 and the same

nevsk [136]

Answer:

x = 8

Step-by-step explanation:

9(x - 4) = 2(x + 10)

9x - 36 = 2x + 20

7x = 56

x = 8

Please mark as brainliest :)

6 0

3 years ago

Multiply the polynomials * –6w(2w2 - 5)

Paul [167]

Answer:

-12w^3 + 30w.

Step-by-step explanation:

–6w(2w^2 - 5) Using the distributive law:

= -6w* 2w^2 - 6w*-5

= -12w^3 + 30w.

5 0

3 years ago

Need help with all questions !!! Get a brainiest answer and a thanks !!

stich3 [128]

1) carrots= 5/12 peas= 2/12 potatoes=1/12
corn= 4/12

2) there are more carrots than peas. there are more corn than potatoes.

3) 2/3

4) separate like number 3 but instead of corn put carrots and leave the peas.

6 0

3 years ago

GIVING BRIANLIEST PLS HELP

Ivenika [448]

Step-by-step explanation:

a) Line AB ll DC

b) Line GH acts as a transversal.

c) <10 ; <12 , <9 ; <11

d) <8 = 180° - 120° = 60°(Ans)

<6 = 120°(Ans)

<5 = 60°(Ans)

<4 = 60°(Ans)

<3 = 120°(Ans)

<2 = 120°(Ans)

<1 = 60°(Ans)

5 0

3 years ago

Read 2 more answers

How can I find the exact distance between the points(√7,-√2)and (4√7,5√2)

chubhunter [2.5K]

$\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
&({{ \sqrt{7}}}\quad ,&{{ -\sqrt{2}}})\quad 
% (c,d)
&({{4\sqrt{7}}}\quad ,&{{ 5\sqrt{2}}})
\end{array}~~~
% distance value
d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}
\\\\\\
$

$\bf d=\sqrt{[4\sqrt{7}-\sqrt{7}]^2~+~[5\sqrt{2}-(-\sqrt{2})]^2}
\\\\\\
d=\sqrt{(4\sqrt{7}-\sqrt{7})^2~+~(5\sqrt{2}+\sqrt{2})^2}\implies d=\sqrt{(3\sqrt{7})^2~+~(6\sqrt{2})^2}
\\\\\\
d=\sqrt{3^2\cdot 7~~+~~6^2\cdot 2}\implies d=\sqrt{63+72}\implies d=\sqrt{135}
\\\\\\
\begin{cases}
135=5\cdot 3\cdot 3\cdot 3\\
\qquad 5\cdot 3^2\cdot 3\\
\qquad 15\cdot 3^2
\end{cases}\implies d=\sqrt{15\cdot 3^2}\implies d=3\sqrt{15}$

8 0

3 years ago