<span>Considering that Seth travels with constant speed <span><span>v=<span>dt</span></span><span>v=<span>dt</span></span></span>, then <span><span>v=<span>157.1</span>=<span>x3600</span></span><span>v=<span>157.1</span>=<span>x3600</span></span></span> where <span>xx</span> is the distance traveled in 1 hour. So his velocity would be x miles/hour. By computing <span><span>x=<span><span>3600⋅1</span>57.1</span>=63.047</span><span>x=<span><span>3600⋅1</span>57.1</span>=63.047</span></span>, thus Seth travels at a speed of <span><span>63.047miles/hour</span><span>63.047miles/hour</span></span></span>
