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3 years ago

What is the value of x?

Mathematics

2 answers:

olganol [36]3 years ago

8 0

This shape is 540 degrees

100+100+112+89+x=540
X=139

Hope this helps !

Nataly_w [17]3 years ago

5 0

Answer:

139

Step-by-step explanation:

a pentagon has degrees that add up to 540 so considering youre given 401 degrees the remaining angle has to be 139

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What is the perimeter , in feet , of the polygon 15,22,10,18,14,5,5,16

Alinara [238K]

You just add all the sides together for perimeter
the answer is105

5 0

3 years ago

A glider flies 13 miles north from the airport and then 24 miles diagonally southeast. Approximately how far west does the glide

NISA [10]

Answer:

20.2 miles

Step-by-step explanation:

This can be described by the three sides of a right angled triangle. Let the distance of the glider to the airport be represented by x, applying the Pythagoras theorem:

$/hyp/^{2}$ = $/adj1/^{2}$ + $/adj2/^{2}$

$/24/^{2}$ = $/x/^{2}$ + $/13/^{2}$

576 = $x^{2}$ + 169

$x^{2}$ = 576 - 169

= 407

x = $\sqrt{407}$

= 20.1742

x = 20.2 miles

The glider has to fly 20.2 miles to return to the airport.

8 0

3 years ago

D^2(y)/(dx^2)-16*k*y=9.6e^(4x) + 30e^x

MA_775_DIABLO [31]

The solution depends on the value of $k$ . To make things simple, assume $k>0$ . The homogeneous part of the equation is

$\dfrac{\mathrm d^2y}{\mathrm dx^2}-16ky=0$

and has characteristic equation

$r^2-16k=0\implies r=\pm4\sqrt k$

which admits the characteristic solution $y_c=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}$ .

For the solution to the nonhomogeneous equation, a reasonable guess for the particular solution might be $y_p=ae^{4x}+be^x$ . Then

$\dfrac{\mathrm d^2y_p}{\mathrm dx^2}=16ae^{4x}+be^x$

So you have

$16ae^{4x}+be^x-16k(ae^{4x}+be^x)=9.6e^{4x}+30e^x$
$(16a-16ka)e^{4x}+(b-16kb)e^x=9.6e^{4x}+30e^x$

This means

$16a(1-k)=9.6\implies a=\dfrac3{5(1-k)}$
$b(1-16k)=30\implies b=\dfrac{30}{1-16k}$

and so the general solution would be

$y=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}+\dfrac3{5(1-k)}e^{4x}+\dfrac{30}{1-16k}e^x$

8 0

3 years ago

5. Assuming that a is not equal to c, find the x-value of the intersection point of the lines y = ax +b and y = cx + d.

Ostrovityanka [42]

The x-value of the intersection point of the lines is ( d - b)/(a-c)

<h3>Intersection of lines</h3>

Given the equation of a line expressed as;

y = ax +b and;

y = cx + d.

Equating both lines, we will have:

ax + b = cx + d

Make x the subject of the formula:

ax - cx = d = b

x (a-c) = d - b

x = ( d - b)/(a-c)

Hence the x-value of the intersection point of the lines is ( d - b)/(a-c)

Learn more on intersecting lines here: brainly.com/question/2065148

7 0

2 years ago

PLEASE HELPP!!!

jarptica [38.1K]

Answer:

Reason 4. Division Property of Equality

Step-by-step explanation:

It should be Multiplication Property of Equality instead, which is:

If given a = b

then a × c = b × c

5 0

3 years ago

What is the value of x?​

What is the value of x?