Answer:
42.29 g of BrF₃.
Explanation:
Molar mass of OF2 = 16 + (2 * 19)
= 54 g/mol
Number of moles of OF₂ = mass / molar mass
= 25/54
= 0.46 mol.
Number of OF₂ molecules = number of moles * avogadros constant
= 0.46 * 6.022 x 10²³
= 2.8 x 10^23 molecules of OF2.
Since each OF₂ molecule has 2 Fluorine atoms,
Number of Fluorine atoms in 25.0 g of OF₂ = 2 x 2.8 x 10²³
= 5.576 x 10²³ atoms of Fluorine.
Since 1 BrF₃ molecule has 3 Fluorine atoms,
number of BrF₃ molecules = Number of Fluorine atoms / 3
= 5.576 x 10²³ / 3
= 1.8587 x 10²³ molecules of BrF₃.
Number of moles of BrF₃ = number of molecules of BrF₃ / Avogadros constant
= (1.8587 x 10²³) / (6.022 x 10²³ )
= 0.30865 moles of BrF₃.
Molar mass of BrF₃ = 80 + (19 * 3)
= 137 g/mol
mass of BrF₃ = number of moles * molar mass
= 0.30865 * 137
= 42.29 g of BrF₃.
Answer:
The relationship is expressed as follows: ![K_{a} = \frac{[H+][A-]}{[HA]}](https://tex.z-dn.net/?f=K_%7Ba%7D%20%3D%20%5Cfrac%7B%5BH%2B%5D%5BA-%5D%7D%7B%5BHA%5D%7D)
Explanation:
Most acidic substances are weak acids and are therefore only partially ionized in acqeous solution. We cab use the equilibrium constant for the ionization of acid to express the extent to which the weak acid ionizes. If we represent a general weak acid as HA, we can write the equation for its ionization reaction like this:
![K_{a} = \frac{[H+][A-]}{[HA]}](https://tex.z-dn.net/?f=K_%7Ba%7D%20%3D%20%5Cfrac%7B%5BH%2B%5D%5BA-%5D%7D%7B%5BHA%5D%7D)
To calculate the pH of a weak acid, we use the equilibrium concentration of the reacted species and product.
Take for example:
HA → H + A⁻
where A id the conjugate base.
Knowing that x amount of acid reacts, we can solve like this:
HA → H + A⁻
H+ = antilog (pH)
thus, the pH of the acid is equals to H+ (initial) - H+ (equilibrium) ≈ H+ (initial)
Answer 1
Explanation
Because it’s 1