Li2O + H2O → 2LiOH
This is the answer
3rd blank write 2
Explanation: We are given three balloon carrying different charges: One having positive charge, one having negative charge and one having no charge.
When we bring positive rod near these three balloons, all of them behave differently.
According to the Coulomb's Law:
Like charges repel each other and unlike charges attract each other.
- When we bring positive rod towards the balloon having positive charge, the balloon will move away from the rod, because like charges repel each other.
- When we bring positive rod near negative balloon, the balloon will be attracted to the rod because unlike charges attract each other.
- But, when we bring positive rod towards the balloon having no charge, the charges will be induced in the balloon. Although the balloon is neutral in nature but it will still carry some +ve or -ve charges. So, when the positive rod is bought near neutral ball, the negative side of the balloon will get attracted towards the rod and positive side will be repelled. From this, we say that the rod has induced some charges in the balloon.
Answer:
The procedure you will use in this exercise exploits the difference in acidity and solubility just described.
(a) you will dissolve your unknown in ethyl acetate (an organic solvent). All of the possible compounds are soluble in ethyl acetate.
(b) you will extract with sodium bicarbonate to remove any carboxylic acid that is present.
(c) you will extract with sodium hydroxide to remove any phenol that is present.
(d) you will acidify both of the resulting aqueous solutions to cause any compounds that were extracted to precipitate.
Answer:
I think that it is A I am sorry if I am wrong
Explanation:
